So this is a lot of work but ghe answers are (fix)
Answer:
<u>There are:</u>
- 6 red balls - R
- 5 black balls - B
- Total number = 11 balls
<h3>A. Without replacement</h3>
i. <u>Two blacks </u>
ii. <u>The first is black</u>
or, alternatively
- P(BR or BB) = 5/11*6/10 + 2/11 = 3/11 + 2/11 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 2/11 + 6/11*5/10 = 2/11 + 3/11 = 5/11
<h3>B. With replacement</h3>
i. <u>Two blacks </u>
- P(BB) = 5/11*5/11 = 25/121
ii. <u>The first is black</u>
or alternatively
- P(BR or BB) = 5/11*6/11 + 25/121 = 30/121 + 25/121 = 55/121 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 5/11*5/11 + 6/11*6/11 = 25/121 + 36/121 = 61/121
Answer:
B
Step-by-step explanation:
Look at the X and Y coordinates carefully. X and Y coordinates are swapped and Y coordinate got negative sign.
Abd is a right angled triangle so by pythagoras we know
and to calculate h we need to use the sine rule
i hope this helps
Find f(-2) f(x)=9x^2-5x+2
f(-2) means replace x in the equation with -2:
f(-2)=9(-2)^2-5(-2)+2
= 9(4) +10 + 2
= 36 +10 + 2
= 48
f(-2) = 48
