<img src="https://tex.z-dn.net/?f=%20-%202%20%5Cleqslant%20x%20-%203%20%3C%204" id="TexFormula1" title=" - 2 \leqslant x

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Alecsey [184]

3 years ago

; 4" alt=" - 2 \leqslant x - 3 < 4" align="absmiddle" class="latex-formula">
How do I solve this?

Mathematics

1 answer:

Stella [2.4K]3 years ago

3 0

Answer:

1 ≤ x < 7

Step-by-step explanation:

−2+3≤x−3+3<4+3 (Add 3 to all parts)

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PLEASEEEEE help!!!!!!!!!!!!

Yuliya22 [10]

Answer:

2st

Step-by-step explanation:

because only 34 can be divided by 17 and there arent enough of s and ts

6 0

2 years ago

Find the maximum rate of change of f(x,y,z=x y/z at the point (2, -3, 5 and the direction in which it occurs. maximum rate of ch

kherson [118]

$f(x,y,z)=x+\dfrac yz$
$\implies \nabla f(x,y,z)=\left(1,\dfrac1z,-\dfrac y{z^2}\right)$
$\implies \nabla f(2,-3,5)=\left(1,\dfrac15,\dfrac3{25}\right)$

The maximum rate of change is then

$\|\nabla f(2,-3,5)\|=\dfrac{\sqrt{659}}{25}$

which occurs in the direction of $\nabla f(2,-3,5)$ above.

6 0

3 years ago

What is the equation of the line that passes through the points (4/5,1/5) and (1/2,3/2)?

Setler [38]

Answer:

$y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})$ point-slope form

$13x+3y=11$ (standard form)

Let me know if you prefer another form.

Step-by-step explanation:

The slope of a line can be found using $\frac{y_2-y_1}{x_2-x_1}$ provided you are given two points on the line.

We are.

Now you can use that formula. But I really love to just line up the points vertically then subtract them vertically then put 2nd difference over 1st difference.

(4/5 , 1/5)

-( 1/2 , 3/2)

-----------------

3/10 -13/10

2nd/1st = $\frac{\frac{-13}{10}}{\frac{3}{10}}=\frac{-13}{3}$ is our slope.