Question

Evaluate sin(sin^-1 √3/2) and assume that all angles are in Quadrant I.

Answer 1

Answer:

B)  $\frac{\sqrt{3}}{2}$.

Step-by-step explanation:

Given : $sin(sin^{-1}(\frac{\sqrt{3}}{2})$.

To find : Evaluate.

Solution : We have given

$sin(sin^{-1}(\frac{\sqrt{3}}{2})$.

By the identity : $sin(sin^{-1}(x)$ = x .

Here, x = $\frac{\sqrt{3}}{2}$.

So, $sin(sin^{-1}(\frac{\sqrt{3}}{2})$ =  $\frac{\sqrt{3}}{2}$.

Therefore, B)  $\frac{\sqrt{3}}{2}$.

Answer 2

Answer:

B. √3/2

Step-by-step explanation:

Sin[sin⁻¹ (√3/2)]

sin⁻¹ (√3/2 = 60°

60° is the acute angle, in the first quadrant

Therefore;

Sin[sin⁻¹ (√3/2)] = sin 60° ; since sin⁻¹ (√3/2 = 60°

Sin 60° = √3/2

Therefore, the answer = √3/2