Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Answer:
Step-by-step explanation:
Remark
The angles are marked as alternate interior angles. To be parallel, they must be equal. In other words x - 20 must equal 52. That's all you have to do. Just equate the 2 givens and solve.
Givens
x - 20 is one angle
52 is the other.
Solution
x - 20 = 52 Add 20 to both sides.
x - 20 + 20 = 52 +20 Combine
x = 72
Answer: C
Answer:
its . 6
Step-by-step explanation:
e2020
Answer:
x = 53
Step-by-step explanation:
Vertical angles are equal
so
3x - 10 = 149
3x = 159
x = 159 / 3
x = 53
An angle that is *bisected* is an angle that is *cut in half*. What angle is half of 22 degrees?