Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
Answer : amar makes $8 per hour
This is a division problem. You can use the standard algorithm of 128/ 5. Or you can create equal groups (draw five circles) and count out eggs until you distribute them all. I would start with 20 in each circle. That would be 20+ 20+ 20+ 20+ 20= 100 Then think 128-100= 28 Next count by 5's. 5+ 5+ 5+ 5+ 5= 25 Then think what is 28-25= 3 so 128/ 5= 25 with a reminder of 3 eggs left over.
Answer:
$44
Step-by-step explanation:
She has 79 AFTER her grandfather gave her 35. So you would subtract 35 from the 75 and get $44
Answer:
The two points solutions to the system of equations are: (2, 3) and (-1,6)
Step-by-step explanation:
These system of equations consists of a parabola and a line. We need to find the points at which they intersect:

Since we were able to factor out the quadratic expression, we can say that the x-values solution of the system are:
x = 2 and x = -1
Now, the associated y values we can get using either of the original equations for the system. We pick to use the linear equation for example:
when x = 2 then 
when x= -1 then 
Then the two points solutions to the system of equations are: (2, 3) and (-1,6)