Given that a coupon for $15 off will be applied on purchases over $100, the given discounted price of the jacket is $203. Since this is the discounted price, then it should be the price after the coupon has been used. To find the retail (or original) price, we simply add 15 back to 203. So the retail price should be $218.
Answer: none
Step-by-step explanation:
(A)
(16÷32/10) ×2 + 0.2×(90)
Using bodmas principle ; solve bracket
(16×10/32)×2 + (2/10×90)
10+18 =28
(B)
{(16÷32/10) × (2+2/10)} ×90
Open brackets
{(16×10/32) × (22/10)} ×90
(5×11/5) ×90
11×90 = 990
(C)
16÷{(32/10×2) + (2/10×8)} +82
Open brackets, solve division first, dolled by addition
16÷(32/5 + 8/5) +82
16÷(40/5) +82
16÷8 +82
2+82= 84
(D)
[16÷(32/10 ×2) + 0.2× (90)]
16÷ (32/5) + 2/10 ×90
Solve division
16×5/32 + 18
5/2 + 18
L.c.m of denominator (2&1) =2
(5+36) / 2 = 41/2
=20.5
Answer:
A - Hopes this helps.
Step-by-step explanation:
148
Step-by-step explanation:
44 3/4 : 11/4 =?
if you do this you will find the solution =>years
