Answer:
D
Step-by-step explanation:
hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>
Answer:
See below for answers
Step-by-step explanation:
Do you mean 
or 
?
Use the formula 
where 
is the amplitude, 
is the phase shift, 
is the vertical shift, and the period is 
.
Assuming your first case is true, the amplitude would be 
, your period is 
, and your midline/vertical shift is 
.
Assuming your second case is true, everything but the vertical shift stays the same. It would be 
in this case.
Convert 1 3/5 to an improper fraction;
-1 × 5 + 3/5 ÷ -2/3
Simplify 1 × 5 to 5
-5 + 3/5 ÷ -2/3
Simplify 5 + 3 to 8
-8/5 ÷ -2/3
Use this rule: a ÷ b/c = a × c/b
-8/5 × 3/-2
Use this rule; a/b × c/d = ac/bd
-8 × 3/5 × - 2
Simplify 8 × 3 to 24
-24/5 × -2
Simplify 5 × -2 to -10
- 24/-10
Move the negative sing to the left
-(-24/10)
Simplify 24/10 to 12/5
-(-12/5)
Simplify brackets
12/5
Convert to a mixed fraction
<u>= 2 2/5</u>
