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Naya [18.7K]
3 years ago
8

If 22.99 g of sodium and 35.45 g of chlorine fully react, how much sodium chloride forms?​

Chemistry
1 answer:
matrenka [14]3 years ago
3 0

Answer:

The answer to your question is: HCl = 58.44 g

Explanation:

To solve this problem, we must remember the law of conservation of mass that says that, matter cannot be created or destroyed, only changes its form.

That means that, the mass of the reactants must be equal to the mass of the products.

               Process

                    Sodium (Na)  +    Chlorine (Cl)   ⇒     Sodium chloride (HCl)

                         22.99 g              35.45 g                            x

              22.99 + 35.45 = HCl

              HCl = 58.44 g

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3 years ago
Zn(s)+2HCl(aq)->ZnCl2(aq)+H2(g)
kobusy [5.1K]
To answer this we need to assume that at STP 1 mol of a substance is equal to 22.4 L. We use this data for the calculations. 
Statement 1
2 mol HCl (1 mol H2 / 2 mol HCl) = 1 mol H2 thus at STP 22.4 L H2
<em>This statement is false.</em>
Statement 2
1 L Zn (1 mol Zn / 22.4 L Zn) (1 mol H2 / 1 mol Zn) (22.4 L H2 / 1 mol H2) = 1L H2
<em>This statement is true.</em>
Statement 3
65.39 g Zn (1 mol Zn / 65.39 g Zn) (1 mol H2 / 1 mol Zn) = 1 mol H2
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Statement 4
1L HCl (1 mol HCl / 22.4 L HCl)(1 mol H2 / 2 mol HCl) = 0.022 mol H2
<em>This statement is false.</em>
7 0
3 years ago
Read 2 more answers
What mass of Cu(s) is electroplated by running 30.0 A of current through a Cu2 (aq) solution for 4.00 h
Alborosie

Answer:

The correct answer is "142 g".

Explanation:

According to the question,

⇒ Cu^2+(aq)+2e^  ------> Cu(s)

where,

Z = 2

F = 96500c

C = 30 A

t = 4h

 = 4\times 60\times 60

 = 14400 \ sec

We know that,

Atomic mass of Cu(M) = 63.5 g/mole

Now,

⇒ W=\frac{Mct}{ZF}

On putting the values, we get

        =\frac{63.5\times 30\times 14400}{2\times 96500}

        =\frac{27432000}{193000}

        =142 \ g

3 0
3 years ago
En un depósito hay 800 litros de agua. Por la parte superior un tubo vierte en el depósito 25 litros por minuto, y por la parte
WINSTONCH [101]

Answer:

Ninguno estará en el agua después de 15 minutos.

Explanation:

Tomar 25 + 30 = 55 por minuto de agua que sale. Como ahora sabemos eso, tómese 55 minutos por 15 minutos. Debe obtener 825, por lo tanto, no quedará agua.

- Avíseme si esto es incorrecto o si desea una explicación más detallada. Espero que esto haya ayudado!

4 0
4 years ago
If you have 100 g of radioactive isotope with a half-life of 10 years:
labwork [276]
<h3>Answer:</h3>

#1. 50 g

#2. 25 g

#3. 4 half lives

<h3>Explanation:</h3>

<u>We are given;</u>

  • Original mass of a radioisotope as 100 g
  • Half life of the radioisotope as 10 years

We need to answer the questions:

#a. Mass remaining after 10 years

Using the formula;

Remaining mass = Original mass × 0.5^n , where n is the number of lives.

In this case, since the half life is 10 years then n is 1

Therefore;

Remaining mass = 100 g × 0.5^1

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Therefore, 50 g of the isotope will remain after 10 years

#b. Mass of the isotope that will remain after 20 years

Remember the formula;

Remaining mass = Original mass × 0.5^n

n = Time ÷ half life

n = 20 years ÷ 10 years

   = 2

Therefore;

Remaining mass = 100 g × 0.5^2

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Thus, 25 g of the isotope will be left after 20 years

#3. Number of half lives in 40 years

1 half life = 10 years

But; n = time ÷ half life

          = 40 years ÷ 10 years

          = 4

Thus, the number of half lives in 40 years is 4.

6 0
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