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Anon25 [30]
3 years ago
14

Alex saw a rusty old car in an abandoned lot. Because he had recently read about chemical reactions, he began to wonder how the

rust formed. What happened to cause the rust on the steel car?
A. A decomposition chemical reaction took place when the iron in the steel mixed with oxygen to form rust.
B. oxygen in the air reacted with the paint on the car and formed rust
C. A physical change took place in the steel of the car to form rust
D. Oxygen in the air chemically combined with iron in the steel to form rust.
Chemistry
1 answer:
Mice21 [21]3 years ago
8 0

The answere is A .......


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Which word means the remains or imprints of once-living organisms found in layers of rock
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Fossils is the answer
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You measure salt water in a tank to have a density of 1.02 g/mL. A balloon weighs 2.0 g and you weights have a mass of 30.0 g ea
Elden [556K]

Weight of the balloon = 2.0 g

Six weights each of mass 30.0 g is added to the balloon.

Total mass of the balloon = 2.0 g + 6*30.0 g = 182 g

Density of salt water = 1.02 g/mL

Calculating the volume from mass and density:

182g*\frac{mL}{1.02g} =178mL

Converting the volume from mL to cubic cm:

178 mL * \frac{1cm^{3} }{1mL} =178cm^{3}

Assuming the balloon to be a sphere,

Volume of the sphere = \frac{4}{3}πr^{3}

178 cm^{3} = \frac{4}{3}(\frac{22}{7})r^{3}

r = 3.49 cm

Radius of the balloon = 3.49 cm

Diameter of the balloon = 2 r = 2*3.49 cm = 6.98cm


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3 years ago
What is the initial reactant for a fusion reaction in the sun? <br><br> a) Iron-56<br> b) Hydrogen-1
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4 years ago
Determine the concentration of hydronium and hydroxide ions in a solution that has a pH of 1.6.
Veronika [31]

Answer:

The answer to your question is [H₃O⁺] = 0.025   [OH⁻] = 3.98 x 10⁻¹³

Explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 1.6

Process

Use the pH formula to calculate the [H₃O⁺], then calculate the pOH and with this value, calculate the [OH⁻].

pH formula

pH = -log[H₃O⁺]

-Substitution

1.6 = -log[H₃O⁺]

-Simplification

[H₃O⁺] = antilog (-1,6)

-Result

[H₃O⁺] = 0.025

-Calculate the pOH

pOH = 14 - pH

-Substitution

pOH = 14 - 1.6

-Result

pOH = 12.4

-Calculate the [OH⁻]

12.4 = -log[OH⁻]

-Simplification

[OH⁻] = antilog(-12.4)

-Result

[OH⁻] = 3.98 x 10⁻¹³

5 0
3 years ago
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