Answer : The partial pressure of
is, 222.93 torr
Explanation :
Half-life = 2.81 hr = 168.6 min
First we have to calculate the rate constant, we use the formula :



Now we have to calculate the partial pressure of 
The balanced chemical reaction is:

Initial pressure 760 0 0
At eqm. (760-2x) 4x x
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = time passed by the sample = 215 min
a = initial pressure of
= 760 torr
a - x = pressure of
at equilibrium = (760-2x) torr
Now put all the given values in above equation, we get:


The partial pressure of
= x = 222.93 torr
Answer:
Explanation:
It is possible to answer this question knowing Hess's law that says you can sum half-reactions enthalpy cahnge to obtain enthalpy change of the total reaction. Using the reactions:
<em>(1) </em>2NO(g) → N₂(g)+O₂(g) ΔH = -180,6 kJ
<em>(2) </em>N₂(g) + O₂(g) + Cl₂(g) → 2NOCl(g) ΔH = +103,4 kJ
The reverse reactions of (1) and (2) are:
<u>N₂(g)+O₂(g)</u> → 2NO(g) ΔH = +180,6 kJ
2NOCl(g) → <u>N₂(g) + O₂(g)</u> + Cl₂(g) ΔH = -103,4 kJ
The sum of these reactions is:
2NOCl(g) → 2NO(g) + Cl₂(g) ΔH = +180,6 kJ -103,4 kJ = <em>77,2 kJ</em>
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I hope it helps!
True becuase the substance changed into another substance which is a example of a chemical reaction.
570/8.5=67.0 58... you only have to take the natural part, si the answer is 67 students
Answer:
3
Explanation:
pH=-log(H+)
- Hope that helps! Please let me know if you need further explanation.