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2 years ago

Simplify (8c^4w^2)^2 show work

Mathematics

1 answer:

muminat2 years ago

7 0

Exponents are not particularly mysterious. They show repeated multiplication. That is ...

... c⁴ = c·c·c·c

... w² = w·w

Then the factor inside parentheses is ...

... 8·c·c·c·c·w·w

The exponent outside parentheses tells you the number of times this is repeated as a factor:

... (8c⁴w²)² = (8·c·c·c·c·w·w)(8·c·c·c·c·w·w)

... = 8·8·c·c·c·c·c·c·c·c·w·w·w·w = 64c⁸w⁴

_____

You can take advantage of the fact that multiplication is repeated addition, so the exponents of the various factors can be found by multiplying the outside exponent by the inside exponents.

$\displaystyle\left(8c^{4}w^{2}\right)^{2}=8^{2}\cdot c^{4\cdot 2}\cdot w^{2\cdot 2}\\\\=64c^{8}w^{4}$

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SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

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Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

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2 years ago

In parallelogram abcd, ab=14, bc=20, m(angle)b=54. Find to the nearest tenth the length of diagonal bd, and find measure angle d

muminat

It is is a parallelogram, hence we have to face sides equal in length and the opposite angles are also the same. From the given above we have:
ab=14 and its opposite side cd=14
bc=20 and its opposite side da=20

Solving for the diagonal measurement bd, we have consecutive angles are equal to 180°
∠A+∠B=180°
∠A=180°-54°
∠A=126° , ∠B=54° ,∠C=126° and ∠D=54°
bd²=ab²+da²-2(ab)(da)cos126°
bd²=14²+20²-2*14*20cos126°
bd=30.42 unit

Solving for the angle dbc, we have
cos dbc=bc²+bd²-cd²/a*bc*bd
cos dbc=20²+30.42²-14²/2*20*30.42
dbc=21.76°

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2 years ago

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GREYUIT [131]

<h2>Answer:</h2>

29%

<h2>Explanations:</h2>

Probability is the likelihood or chance that ab event will occur. Mathematically;

Probability = Expected/Total

From the given table, the total number of male student is the total outcome as shown:

Total outcome = 4 +6+ 2 + 2

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If a male freshmen is selected at random, the expected outcome will be 4.

Determine the probability

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Hence the probability that the male student is freshman is approximately 29%

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1 year ago

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Ainat [17]

0.91 = 91/100 = 91%

That's basically it

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