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Makovka662 [10]
3 years ago
7

What expression is quadratic monomial?

Mathematics
1 answer:
grandymaker [24]3 years ago
7 0

Answer:

the solution is x^4. the second one

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The vertices of a parallelogram are shown below.
OleMash [197]
The vertices for the dilated image can be found by multiplying the coordinates of the original image by the scale factor. In this problem, the scale factor is 1/3.

(0,0) ⇒ 0 x 1/3 = 0 ; 0 x 1/3 = 0 ⇒ (0,0)
(27,0) ⇒ 27 x 1/3 = 9 ; 0 x 1/3 = 0  ⇒ (9,0)
(36,30) ⇒36 x 1/3 = 12 ; 30 x 1/3 = 10 ⇒ (12,10)
(9,30) ⇒ 9 x 1/3 = 3 ; 30 x 1/3 = 10 ⇒ (3,10)

Answer is choice D. (3,10)
4 0
3 years ago
Help me pleaseee!!<br> Would appreciate ^^<br> **BRAINLIST, thanks and points***
sergey [27]

Answer:

See below

Step-by-step explanation:

22. 30 = 2 * 3 * 5

23. 126 = 2 * 3 * 3 * 7

24. 4900 = 2 * 2 * 5 * 5 * 7 * 7

25. 39204 = 2 * 2 * 3 * 3 * 3 * 3 * 11 * 11

26. There's no square number

27. The highest common factor are

   30 is 5

   126 is 7

  4900 is 7

 39204 is 11

28. The lowest common factor are

 30 is 2

 126 is 2

 4900 is 2

 39204 is 2

What about you? What did you get?

4 0
3 years ago
The length of a rectangle is 4 in longer than its width. if the perimeter of the rectangle is 28 in , find its area.
ra1l [238]
The area is 45 inches squared

7 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
I rlly need help on this guys it’s due tomorrow!! The outside radius of a truck tire is 11 inches. Approximately how far will th
Sergeeva-Olga [200]

Answer:

207.24 inches

Hope this helps

Step-by-step explanation:

first you need to find the circumference...

2pi R (r=radius=11)

2 x 3.14 x 11 = 69.08         (i'm using 3.14 as pi so yea...)

3 rotations...

69.08 x 3= 207.24 inches

5 0
3 years ago
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