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sleet_krkn [62]

3 years ago

7

I need number 3 please I need this ASAP

1 answer:

zepelin [54]3 years ago

5 0

Answer:

just wanted points. sorry

Step-by-step explanation:

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** HELP ASAPP ** how do u do this!!! (image bellow)

Nikitich [7]

Answer:

x/2 + y/3 = 1

Step-by-step explanation:

using this formula

x/a + y/b = 1 , where a and b are the coordinates of x and y axes respectively.

7 0

2 years ago

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A share of stock in the Lofty Cheese Company is quoted at 25 1/4. Suppose you hold 30 shares of that stock, which you bought at

Marizza181 [45]

I don't know the options, but I can say this:

if you bought it at 20 1/4 and you sell them at 25 1/4 then your win pro stock is the difference between those two numbers, which is 5. (25 1/4-20 1/4 =5)

and if you sell all of them, your profit will be 30*5=150 dollars.

6 0

3 years ago

A normal distribution has a mean of 10 and a standard deviation of 1. What is the probability of selecting a number that is at m

Len [333]

Answer: 0.500

Step-by-step explanation:

Given : A normal distribution has a mean $(\mu)$ of 10 and a standard deviation $(\sigma)$ of 1.

Let x be a random variable that represents numbers .

The probability of selecting a number that is at most 10 will be

$P(x\leq10)=P(\dfrac{x-\mu}{\sigma}\leq\dfrac{10-10}{1})\\\\=P(z\leq0)=0.500$

As the area occupied by standard normal curve less than equal to 0 = 0.500

So, required probability = 0.500

3 0

2 years ago

What is 388×63+20-45+21

GrogVix [38]

24440 is you answer :)

5 0

3 years ago

Read 2 more answers

An experiment is completed where a coin is flipped and a six-sided die (singular for dice) is rolled. The outcomes from the expe

victus00 [196]

Answer:

1) $16\frac{2}{3}$ % or 20%

Step-by-step explanation:

Given that:

An experiment which is carried out by flipping a coin and rolling six sided die.

The outcomes can be:

{H1, H2, H3, H5, H6, T1, T1, T2, T3, T5}

As per question statement:

Number of outcomes having tails and an odd number greater than one is 2 (i.e. T3 and T5)

Total number of outcomes here is 10.

Therefore, to find the percentage, we use the following formula:

$\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\times 100$

$\Rightarrow \dfrac{2}{10}\times 100 = 20\%$

As per question statement, the answer is 20%.

If we consider all the outcomes, i.e.

{H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}

Total number of outcomes = 12

The percentage will come out be :

$\Rightarrow \dfrac{2}{12}\times 100 = 16\frac{2}{3}\%$

7 0

2 years ago