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matrenka [14]
3 years ago
5

4x+ 3y -2z=35, 2x-3y+z=-6, x+2y+3z=-5, solve for x,y and z

Mathematics
1 answer:
Mkey [24]3 years ago
3 0
1. X = \frac{35}{4}+\frac{\left( -3\right) \ Y}{4}+\frac{z}{2}$$
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115 + ( -215 ) + 315 + ( -415) + 515 + ... + 3915 + ( -4015 ) =
Likurg_2 [28]
215 because you would add and subtract the numbers as you go them you come out with your answer
5 0
4 years ago
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Find the distance between the given points: (2, -2) and (-4, -7)
miv72 [106K]
Formula: sqr((x2-x1)^2 + (y2-y1)^2)
sqr((-4-2)^2 + (-7+2)^2)
sqr(-6)^2 + (-5)^2)
sqr(36)+(25)) = sqr(61)
The answer is A. sqr(61)
3 0
3 years ago
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Function A and Function B are linear functions. Compare the two functions and choose all that are correct.
Olegator [25]

Answer:

  2 .The slope of Function A is less than the slope of Function B

Step-by-step explanation:

A graph of Function A shows it has a y-intercept of 4, the same as that of Function B. (Statements 3 and 4 are not correct.)

The slope of Function A is 2, which is less than the slope of 3 that Function B has. (Statement 2 is correct; statement 1 is not.)

_____

<em>More detailed working</em>

The slope of Function A can be figured easily between the points with x-values that differ by 1:

  m = (y3 -y2)/(x3 -x2) = (24-22)/(10-9) = 2/1 = 2 . . . . . Fun A has slope of 2.

The slope of Function B is the coefficient of x in the equation: 3.

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The y-intercept of Function A can be found starting with point-slope form:

  y -22 = 2(x -9)

  y = 2x -18 +22

  y = 2x +4 . . . . . . . slope-intercept form

The intercept of +4 is the same as that of Function B.

5 0
3 years ago
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What is the value of x for the equation 2^5 ∙ 2^x = 2^8
netineya [11]

Answer:

x=3

Step-by-step explanation:

5 0
3 years ago
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Rajesh invested $30,000 into an account that compounds interest monthly at a rate of 2.16%. He has made arrangements to withdraw
Bond [772]

By Evaluating the Compound Interest, we come to know that Rajesh will have enough money in the account to cover all of the required loan payments.

The Principal Amount(P) = $30,000

Rate of Interest (r) = 2.16 %

Time(t) = 10 years

Number of Times it is Compounded in a year(n) = 12

Now, we have

A =P(1+\frac{r}{100n}) ^{nt}

Putting all the values, we evaluate the amount,

A =30,000(1+\frac{2.16}{100*12}) ^{12*10}\\\\A = 30,000 * 1.240\\A = 37,225.84

Hence, the Amount after Compound Interest = $37,225.87

Now, The loan amount that he pays = 300 *12*10 = $ 36,000

Yes, he will have enough money in the account to cover all of the required loan payments.

To read more about Compound Interest, visit brainly.com/question/29335425

#SPJ1

5 0
1 year ago
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