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3 years ago

6

Job natural peanut butter normally cost four dollars today it’s on sale for $3.60 what is the percentage of the discount

1 answer:

Rzqust [24]3 years ago

5 0

We can make an equation that would help this. X will be the discount rate.
4x=3.60
Now, we need to solve the equation to find what X is.
Let's divide each side by 4.
x=.9
So, we know that the item was sold for 90% of what it was before, meaning that it has a 10% discount.

You might be interested in

Sq is an angle bisector m <qst=2x and m <qsr=3x-10 what is <rst

defon

Answer:
∠RST = 40°

Explanation:
We are given that:
SQ bisects angle RST.
This means that:
∠QST = ∠QSR
2x = 3x - 10
10 = 3x - 2x
x = 10

Therefore:
∠QST = 2x = 2(10) = 20°
∠QSR = 3x - 10 = 3(10) - 10 = 30 - 10 = 20°
Note that both angles are equal.

Now, we can get ∠RST as follows:
∠RST = ∠QST + ∠QSR
∠RST = 20 + 20 = 40°

Hope this helps :)

6 0

3 years ago

5y + 2(11 - 4y) = 82 + y<br> Help Needed Asap

ryzh [129]

Answer:

y=−15

Hope this helps! Please mark Brainliest!

4 0

3 years ago

Read 2 more answers

What is the positive solution to the equation 0=⅓x²-3

sammy [17]

Add 3, multiply by 3, and take the positive square root.
3 = (1/3)x²
9 = x²
√9 = 3 = x

The positive solution to the equation is x = 3.

7 0

2 years ago

Nacir is buying school supplies. He purchases 8 notebooks for $12.48. How much does Nacir pay for 1 notebook?

Dmitry [639]

12.48/8= 1.56 per notebook

3 0

3 years ago

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It is believed that 3% of people actually have this predisposition. The genetic test is 99% accurate if a person actually has th

fiasKO [112]

Answer:

Required Probability = 0.605

Step-by-step explanation:

Let Probability of people actually having predisposition, P(PD) = 0.03

Probability of people not having predisposition, P(PD') = 1 - 0.03 = 0.97

Let PR = event that result are positive

Probability that the test is positive when a person actually has the predisposition, P(PR/PD) = 0.99

Probability that the test is positive when a person actually does not have the predisposition, P(PR/PD') = 1 - 0.98 = 0.02

So, probability that a randomly selected person who tests positive for the predisposition by the test actually has the predisposition = P(PD/PR)

Using Bayes' Theorem to calculate above probability;

P(PD/PR) = $\frac{P(PD)*P(PR/PD)}{P(PD)*P(PR/PD)+P(PD')*P(PR/PD')}$

= $\frac{0.03*0.99}{0.03*0.99+0.97*0.02}$ = $\frac{0.0297}{0.0491}$ = 0.605 .

7 0

3 years ago