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4 years ago

Mathswatch is to hard please help

Mathematics

2 answers:

mart [117]4 years ago

7 0

A) 80
B) a- corresponding angles
Angles abf and efg are both corresponding angles thereforethey are on the same side of transversal, where it slits the two parallel lines hence they are equal

babunello [35]4 years ago

4 0

Answer:

a) 80

b) A - corresponding angles

Step-by-step explanation:

Angle EFG and angle ABF are corresponding angles.

Corresponding angles are on the same side of the transversal, where it cuts the two parallel lines, and they are equal.

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PLEASE HELP DEW IN 1 hour

Marta_Voda [28]

Answer: B

Step-by-step explanation:

2(—2) + 10 = 6.

2(0) + 6 = 6.

2(2) + 2 = 6.

2(4) + (—2) = 6

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3 years ago

it takes maya 30 minutes to solve 5 logic puzzles,and it takes amy 28 minutes to solve 4 logic puzzles, in minutes per puzzle

Harman [31]

Answer:

MAYA (6 minutes)

Amy (7 minutes)

Step-by-step explanation:

MAYA

Takes Maya 30 minutes to solve 5 Puzzle:

Let's express it as,

30 mins = 5 Puzzle

1 min = x Puzzle

Cross multiply to solve for the number of questions Maya solves in a minute.

It becomes:

30*x = 5*1

30x = 5

x = 30/5

x = 6mins.

It means it takes Maya 6 mins to solve one question.

FOR AMY

Takes Amy 28 mins to solve 4 puzzles.

Let's represent it as:

28 mins = 4 Puzzles

x min = 1 puzzle

Let's solve for x

(28 mins) * (1 puzzle) = 4 * x

28 = 4x

x = 28/4

x = 7 mins

It means, it takes Amy 7 minutes to solve 1 puzzle

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3 years ago

September 2016 gp hyperbole Question 4

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Answer:

Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Find sec 2Theta in exact value

forsale [732]

Answer:

$sec(2\theta)=-\frac{5}{4}$

Step-by-step explanation:

we know that

step 1

Find $cos(\theta)$

we know that

$tan^2(\theta)+1=sec^2(\theta)$

we have

$tan(\theta)=3$

substitute

$3^2+1=sec^2(\theta)$

$sec^2(\theta)=10$

$sec(\theta)=\pm\sqrt{10}$

Remember that

Angle theta lie in Quadrant I

$sec(\theta)$ is positive

$sec(\theta)=\sqrt{10}$

Remember that

$sec(\theta)=\frac{1}{cos(\theta)}$

therefore

$cos(\theta)=\frac{1}{\sqrt{10}}$

step 2

Find $sin(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin(\theta)=tan(\theta)cos(\theta)$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

$tan(\theta)=3$

substitute

$sin(\theta)=(3)(\frac{1}{\sqrt{10}})$

$sin(\theta)=\frac{3}{\sqrt{10}}$

step 3

Find $cos(2\theta)$

we know that

$cos(2\theta)=2cos^2(\theta)-1$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

substitute

$cos(2\theta)=2(\frac{1}{\sqrt{10}})^2-1$

$cos(2\theta)=\frac{1}{5}-1$

$cos(2\theta)=-\frac{4}{5}$

Remember that

$sec(2\theta)=\frac{1}{cos(2\theta)}$

therefore

$sec(2\theta)=-\frac{5}{4}$

8 0

3 years ago