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Elanso [62]
3 years ago
5

Factorise the following

Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0
For a), common terms between them are x & y
Thus, xy(3x+5y)

For b), I'm guessing the answer is (m+n)(x+y)
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Make a conjecture about the next item in the sequence. 6, 9, 7, 10, 8?
inessss [21]

Answer:

"The next term should be 11"

Step-by-step explanation:

If we look closely at the sequence we can see:

second term is 3 more than previous

third term is 2 less than previous

fourth term is 3 more than previous

fifth term is 2 less than previous

We can see a pattern. To get next terms, we add 3, to get next to that, we subtract 2. It goes on like this.

Since 4th term to 5th term is "subtracting 2", logically 5th to 6th term (the term we are wanting) should be "add 3". So the term after 8 would be 11

The next term would be 11

5 0
3 years ago
A grocery store buys cashews for
maxonik [38]

Answer:

9.6

Step-by-step explanation:

20%of 8=8*20/100 =1.6 and the new price of the cashews is1. 6+8=9.6

8 0
2 years ago
Please Assist!<br>What is the answer to this question???<br>​
Phoenix [80]

Answer:

(-5,\frac{1}{2}  )

Step-by-step explanation:

Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}  )

Simply plug in your coordinates into the midpoint formula to find midpoint:

R(-2, 3)

S(-8, -2)

(\frac{-2+-8}{2},\frac{3+-2}{2}  )

(\frac{-10}{2},\frac{1}{2}  )

(-5,\frac{1}{2}  )

3 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
Read 2 more answers
Mr. Herman's class is selling candy for a school fundraiser. The class has a goal of raising $500 by selling C
katovenus [111]

Answer:

2.75 x (c) = 500

Step-by-step explanation:

i think this is it

8 0
2 years ago
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