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VLD [36.1K]
3 years ago
5

How to write all real numbers less than -1 or greater than 1 as an inequality

Mathematics
1 answer:
Citrus2011 [14]3 years ago
8 0

Answer:

|x| > 1

Step-by-step explanation:

The absolute value inequality

|X| > k

where X is an expression in x and k is a non-negative number is solved by solving the equivalent compound inequality

X < -k or X > k

Here you are working backwards. You know you want the compound inequality to be

x < - 1 or x > 1,

so using the variable expression x for the expression X and 1 for k, write the absolute value equation

|x| > 1

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Could someone help me out with this question?
SOVA2 [1]

The simplified form of the difference quotient of equation 9x^2+5x-1 . in the form 9x + 9h + 5.

In question for equation 9x^2+5x-1, simplified to difference quotient in the form of Ax+Bh+C where A, B, C are integers

<h3>What is equation?</h3>

equation is the relationship between variable and represented as  9x^2+5x-1  is example of polynomial equation.

We know that,
for difference quotient
=\frac{f(x+h)-f(x)}{h} \\\frac{9(x+h)^2+5(x+h)-1-9x^2-5x+1}{h}\\\frac{9h^2+9hx+5h}{h}\\9x+9h+5
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Thus, The required value of difference Quotient in the form Ax+Bh+c where A, B and C is 9, 9 and 5 respectively

Learn more about equation here:
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Step-by-step explanation:

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