Answer: Mass of
produced in this reaction was 6.56 grams
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
![CaCO_3(s)+2HCl(aq)\rightarrow H_2O(l)+CO_2(g)+CaCl_2(aq)](https://tex.z-dn.net/?f=CaCO_3%28s%29%2B2HCl%28aq%29%5Crightarrow%20H_2O%28l%29%2BCO_2%28g%29%2BCaCl_2%28aq%29)
Mass or reactants = Mass of
+ mass of
= 16.00 + 64.80 = 80.80 g
Mass of products = mass of aqueous solution + mass of
+ = 74.24 + x g
Mass or reactants = Mass of products
80.80 g = 74.24 + x g
x = 6.56 g
Thus mass of
produced in this reaction was 6.56 grams
Answer:
The ion will repel the substance because it has more protons than electrons.
Explanation:
During the chemical reaction, the solid substance that is insoluble formed during the combination of two aqueous solutions is called a precipitate. The answer is letter C. The precipitation reaction occurs when a salt is formed in the reaction of solutions with salts.
The answer is 1) CF3
Because: the equivalent of Fluorine is -1 so it aims to get an electron so much. which means it's electronegative.
but the equivalent of Hydrogen is +1 so it aims to give an electron. which means it's electropositive.
please mark as brainliest answer
Answer:
s = 4.41 g/L.
Explanation:
¡Hola!
En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:
![PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)](https://tex.z-dn.net/?f=PbCl_2%28s%29%5Crightleftharpoons%202Cl%5E-%28aq%29%2BPb%5E%7B2%2B%7D%28aq%29)
Lo cual hace que la expresión de equilibrio se calcule como:
![Ksp=[Pb^{2+}][Cl^-]^2](https://tex.z-dn.net/?f=Ksp%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5E2)
Y que en términos de la solubilidad molar, s, se resuelve como:
![1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L](https://tex.z-dn.net/?f=1.6x10%5E%7B-5%7D%3Ds%282s%29%5E2%5C%5C%5C%5C1.6x10%5E%7B-5%7D%3D4s%5E3%5C%5C%5C%5Cs%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1.6x10%5E%7B-5%7D%7D%7B4%7D%20%7D%20%5C%5C%5C%5Cs%3D0.0159molPbCl_2%2FL)
Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):
![s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L](https://tex.z-dn.net/?f=s%3D0.0159molPbCl_2%2FL%2A%5Cfrac%7B278.1gmolPbCl_2%7D%7B1molmolPbCl_2%7D%20%5C%5C%5C%5Cs%3D4.41g%2FL)
¡Saludos!