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lara [203]
2 years ago
12

I think I put my in it when I asked Jane about her ex-husbandroot​

Chemistry
1 answer:
ryzh [129]2 years ago
3 0
What does this mean?
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Tema: Métodos de Separação de Misturas – Homogêneas e Heterogêneas;
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Answer:

fjskeowkcnekvo Dee five votes come vote for dog even r

4 0
2 years ago
If the solubility of a gas in water is 5.0g/L when the pressure of the gas above the water is 2.0 atm, what is the pressure of t
Serggg [28]
F the solubility of a gas in water is 5.0g/L when the pressure of the gas above the water is 2.0 atm, what is the pressure of the gas above the water <span>when the solubility of the gas is 1.0 g/L</span>

Here's how to solve this one.
The formula for solubility is 
<span>P1 / P2 = solubility1 / solubility2 </span>
P1=2*1/5= .4 atm

So the correct answer is 0.4 atm.
5 0
3 years ago
Draw the alkyl bromide(s) you would use in a malonic ester synthesis of ethyl 2-methyl-4-pentenoate
Rudik [331]

The structure of the alkyl bromides used in a malonic ester synthesis of ethyl 2-methyl-4-pentenoate are as drawn in the attached image.

<h3>Ethyl 2-methyl-4-pentenoate by Malonic ester synthesis.</h3>

The malonic ester synthesis is a chemical reaction characterized by the alkylation of diethyl malonate or a similar ester of malonic acid at the carbon alpha (directly adjacent) to both carbonyl groups, and subsequently converted to a substituted acetic acid.

Hence, it follows from the structure of Ethyl 2-methyl-4-pentenoate that the alkyl bromides used are Ethyl bromide and methyl bromide.

Read more on Malonic ester synthesis;

brainly.com/question/17237043

6 0
2 years ago
Read 2 more answers
The expression for 11 million km in scientific notation is
kakasveta [241]

1.1 * 10^7 km

I think.

6 0
3 years ago
The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
sweet [91]

Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

                       Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-

Initial conc.                        0.220       0

At eqm.                             (0.220+s)   2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ni^{2+}][CN^-]^2

Now put all the given values in this expression, we get:

3.0\times 10^{-23}=(0.220+s)\times (2s)^2

s=5.84\times 10^{-12}M

Therefore, the maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

7 0
2 years ago
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