All categories

2 years ago

Can someone plz help me? :(

Chemistry

2 answers:

Snezhnost [94]2 years ago

6 0

Answer:

The answer is a. I learned that they can multiply by using your cells

scoray [572]2 years ago

5 0

Answer:

Explanation:

The toxins get released, as they poison and damage your body's cells. They also damage your lungs, heart, and veins that are inside the body.

hope this helps.

You might be interested in

There are two different compounds of sulfur and fluorine.

weqwewe [10]

Atomic mass of F: 19.0 g/mol

Atomic mass of S: 32.1 g/mol

1.18 g F = [1.18 g / 19.0 g / mol] = 0.062 mol F

1 g S = 1 g/ 32.1 g/mol = 0.031 mol S

Divide by 0.031

0.062 mol F / 0.031 = 2 mol F

0.031 mol S / 0.031 = 1 mol S

SF2 Then X = 2

Verification:
F2 = 2*19.0 g = 38 g F
S = 32.1 g

36 gF / 32.1 g S = 1.18 g F / g S

7 0

2 years ago

The decomposition of nitrogen dioxide is described by the following chemical equation:

kow [346]

Answer:

The balanced chemical equation will be " $NO_{2}+O\rightarrow NO+O_{2}$ ".

Explanation:

The given equation is:

$2NO_{2}\rightarrow 2NO+O_{2}$

Step 1:

$2NO_{2}\rightarrow NO+O$ ...(equation 1)

Step 2:

$NO_{2}+O\rightarrow NO+O_{2}$ ...(equation 2)

On adding "equation 1" and "equation 2", we get

⇒ $NO_{2}+NO_{2}+O\rightarrow NO+O+NO+O_{2}$

⇒ $2NO_{2}\rightarrow 2NO+O_{2}$

The second step:

⇒ $NO_{2}+O\rightarrow NO+O_{2}$

3 0

2 years ago

Given the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use i

swat32

Answer:

Explanation:

From the given information:

Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.

Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.

If the molecular weight of camphor = 152.24 g/mol

and it mass = 200 mg

The its no of moles = 200 mg/ 152.24 g/mol

= 1.3137 mmol

Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol

= 6.831 mmol

since the molar mass of NaBH4 = 37.83 g/mol

Then, using the same formula:

No of moles = mass/molar mass

mass = No of moles × molar mass

mass = 6.831 mmol × 37.83 g/mol

mass of NaBH4 used = 258.42 mg

7 0

2 years ago

Please HELP, ASAP! Homework due tomorrow and I need some help.

sweet-ann [11.9K]

Ions are atoms with a charge other than zero. In a neutral atom, the number of protons (positively charged particles) in the nucleus equals the number of electrons orbiting the nucleus.
Atoms can gain or lose electrons (not protons) resulting in a net charge other than zero. Atoms which lose electrons (usually metals) become positively charges, and atoms which gain electrons (usually nonmetals) become negatively charged.

3 0

3 years ago

A. 1.4 m B.1.9m C. 2.4m D. 3.6m

jenyasd209 [6]

Apple the way to my hair and hair is so good and i and my friend are going to sleep at the house and i you can do to me and you can do it and i and you have a lot to do with me some time i to get a little sleep in my room and you have my sleep ritirieuwi u and the only reason

8 0

2 years ago