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2 years ago

What is the surface area of the square pyramid

Mathematics

1 answer:

user100 [1]2 years ago

6 0

Answer:

128 feet squared

Step-by-step explanation:

you multiply 4 by 4 to get 16 ,

then you multiply 7 by 4 and get 28,

also multiply 28 by 4 and get 112 ,

finally add 112 and 16 to get 128

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Write each of the following numerals in base 10. For base twelve, T and E represent the face values ten and eleven, respectively

uysha [10]

(a)

421₅ = 4×5² + 2×5¹ + 1×5⁰

… = 100 + 10 + 1

… = 111

(b)

11101₂ = 1×2⁴ + 1×2³ + 1×2² + 0×2¹ + 1×2⁰

… = 16 + 8 + 4 + 0 + 1

… = 29

(c)

13T₁₂ = 1×12² + 3×12¹ + 10×12⁰

… = 144 + 36 + 10

… = 190

7 0

1 year ago

ANTONII [103]

55/100 or 11/20

Since 55% is 55/100 as a fraction. then at it's simplest form it's 11/20.

4 0

3 years ago

Read 2 more answers

Which is the closest to the curve of best fit for the data shown?

docker41 [41]

Answer:

data shows a positive or negative correlation, we can model the trend in the data using a line of best fit. Example 1 ... A curve of best fit is used to find an equation that best fits a quadratic function.

Step-by-step explanation:

7 0

3 years ago

he production of pipes has a mean diameter of 3.25 inches and a standard deviation of .15 inches. The shape of the distribution

o-na [289]

Answer:

The probability that a randomly chosen part has diameter of 3.5 inches or more is 0.9525

Step-by-step explanation:

$Mean = \mu = 3.25 inches$

Standard deviation = $\sigma = 0.15 inches$

We are supposed to determine the probability that a randomly chosen part has diameter of 3.5 inches or more

$P(Z \geq 3.5)=1-P(z$

Refer the z table for p value

$P(Z \geq 3.5)=1-0.0475\\P(Z \geq 3.5)=0.9525$

Hence the probability that a randomly chosen part has diameter of 3.5 inches or more is 0.9525

7 0

3 years ago

A typical middle-income household in 1980 earned $34,757. A similar household in 2009 earned $38,550. What was the relative incr

S_A_V [24]

Given conditions are :

In 1980's, a typical middle-income household earned= $34,757

In 2009, a similar middle-income household earned= $38,550

And we have to find relative increase in income for these households from 1980 to 2009.

So first we will find the total increase in amounts.

$38550-34757=3793$

Relative increase = $\frac{3793}{34757}*100$

= 10.91% or rounding it off we get approx 11%.

Hence, the answer is 11%.

5 0

3 years ago

Read 2 more answers