ANSWER:
60°
EXPLAINATION:
= 2r + θ/360°× 2 x 227 x 21
64 = 2 x 21 + θ/360° x 2 x 22/7 x 21
64 = 42 + θ/360° x 44 x 3
64 - 42 = θ/360° x 11 x 3
22 = 33θ/90
θ=22×30/11
= 60°
1² + 3² + 4² + 4(n - 1)² = ¹/₃n(2n - 1)(2n + 1)
1² + 3² + 4² + (2n - 2)² = ¹/₃n(2n - 1)(2n + 1)
1 + 9 + 16 + (2n - 2)(2n - 2) = ¹/₃n(2n(2n + 1) - 1(2n + 1))
10 + 16 + (2n(2n - 2) - 2(2n - 2)) = ¹/₃n(2n(2n) + 2n(1) - 1(2n) - 1(1) 16 + (2n(2n) - 2n(2) - 2(2n) + 2(2)) = ¹/₃n(4n² + 2n - 2n - 1)
26 + (4n² - 4n - 4n + 4) = ¹/₃n(4n² - 1)
26 + (4n² - 8n + 4) = ¹/₃n(4n² - 1)
26 + 4n² - 8n + 4 = ¹/₃n(4n²) - ¹/₃n(1)
4n² - 8n + 4 + 26 = 1¹/₃n³ - ¹/₃n
4n² - 8n + 30 = 1¹/₃n³ - ¹/₃n
+ ¹/₃n + ¹/₃n
4n² - 7²/₃n + 30 = 1¹/₃n³
-1¹/₃n³ + 4n² - 7²/₃n + 30 = 0
-3(-1¹/₃n³ + 4n² - 7²/₃n + 30) = -3(0)
-3(-1¹/₃n³) - 3(4n²) - 3(-7²/₃n) - 3(30) = 0
4n³ - 12n² + 23n - 90 = 0
The answer is:t=4 You welcome
Answer:
The payment is
.
Interest paid during the 3-year period is 
Step-by-step explanation:
Hi
<u>The Payment amount</u>
We are going to use the formula below with
and
.
![k=\frac{VP}{[\frac{1-(1+i)^{-n}}{i}] } =\frac{8000}{[\frac{1-(1+0.1)^{-3}}{0.1}] }=3216.92](https://tex.z-dn.net/?f=k%3D%5Cfrac%7BVP%7D%7B%5B%5Cfrac%7B1-%281%2Bi%29%5E%7B-n%7D%7D%7Bi%7D%5D%20%7D%20%3D%5Cfrac%7B8000%7D%7B%5B%5Cfrac%7B1-%281%2B0.1%29%5E%7B-3%7D%7D%7B0.1%7D%5D%20%7D%3D3216.92)
<u>Interest paid during the 3 year</u>







- Sum of Interest paid during the 3 years

Answer:
D = rt
b, slower plane
8.5(3b) - 8.5(b) = 1649
25.5b - 8.5b = 1649
17b = 1649
b = 97mph
3b = 291mph