Answer:
Use photo math, it will explain it all in different forms
The value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
<h3>How to solve for x?</h3>
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows

Take the yz root of both sides
![\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5Byz%5D%7Bx%5E%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Apply the law of indices
![x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Byz%7D%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Divide yz by yz
![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Hence, the value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Read more about equations at:
brainly.com/question/2972832
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Vertex form is y=a(x-h)^2+k
you need to find a perfect square
y=x^2+24x+<u> </u>+29 -<u>
</u>y=x^2+24x+144+29-144
y=(x+12)^2 +29-144
y=(x+12)^2-115
1 times 10^1=10
1 times 10^-1=1/10
1 times 10^-2=1/100
1 ten thousandth is 1/10,000, that is 1 times 10^-4
answer is
1*10⁻⁴