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ycow [4]
2 years ago
7

Answer The forth question I will give u 95 points and the brilliantist

Mathematics
2 answers:
Llana [10]2 years ago
6 0

ANSWER:

60°

EXPLAINATION:

= 2r + θ/360°× 2 x 227 x 21

64 = 2 x 21 + θ/360° x 2 x 22/7 x 21

64 = 42 + θ/360° x 44 x 3

64 - 42 = θ/360° x 11 x 3

22 = 33θ/90

θ=22×30/11

= 60°

miss Akunina [59]2 years ago
3 0

answer

60°

explanation

if you feel it helps, give brainlist

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The domain of y = cos x is _______.
Lana71 [14]

ANSWER

d. The set of all real numbers

EXPLANATION

The basic cosine function ,

y =  \cos(x)

is continuous everywhere.

The function is defined for all real values of x.

The domain is the set all values of x that will make the function defined.

The domain is all real numbers.

The correct choice is D.

6 0
3 years ago
WHAT IS 11/6 simplified I CANT DO THIS MATH IT IS TOOOOO HARDDDDD JK IM JUST TO LAZY >:( thanks
Lisa [10]

Answer:

its 11/6

Step-by-step explanation:

GCD of 11 and 6 is 1

Divide both the numerator and denominator by the GCD

11 ÷ 1

6 ÷ 1

Reduced fraction:  

11/6

5 0
3 years ago
Read 2 more answers
15 points!!! GEOMETRY help please!!<br> Questions attached!
dolphi86 [110]
3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o

Answer:\ \boxed{47^o}

4.
Look at the picture.

Use Pythagorean theorem:

x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8

Used:\ (a+b)^2=a^2+2ab+b^2

Answer:\ \boxed{4.8\ units}

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}

We have: OP:\ y=-\dfrac{3}{2}x+b

Now, we must find the slope of the line perpendicular to the line OP.
We know:

k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1

therefore

-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}

So. We have the answer! :)

Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}

6 0
2 years ago
Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3
solmaris [256]

Given:

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

Now,

\cos (u)=-\sqrt{1-\sin^2 (u)}

\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}

\cos (u)=-\sqrt{1-\dfrac{49}{625}}

\cos (u)=-\sqrt{\dfrac{625-49}{625}}

On further simplification, we get

\cos (u)=-\sqrt{\dfrac{576}{625}}

\cos (u)=-\dfrac{24}{25}

Similarly,

\sin (v)=-\sqrt{1-\cos^2 (v)}

\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}

\sin (v)=-\sqrt{1-\dfrac{16}{25}}

\sin (v)=-\sqrt{\dfrac{25-16}{25}}

\sin (v)=-\sqrt{\dfrac{9}{25}}

\sin (v)=-\dfrac{3}{5}

Now,

\cos (u-v)=\cos u\cos v+\sin u\sin v

\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)

\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}

\cos (u-v)=\dfrac{1 17}{625}

Therefore, the value of cos (u-v) is 0.1872.

6 0
2 years ago
What is the sum of the roots of the polynomial shown below?<br> f(x) = 3r?+ 12x² + 3x - 18
densk [106]

Answer:

24x+3

Step-by-step explanation:

6 0
2 years ago
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