Answer:
The correct option is C
Step-by-step explanation:
The given equation is:
y ≥ 2x - 3
For x= 2
y = 2(2) - 3 = 1
For x=0
y = 2(0) - 3 = -3
WE have two point:
(2,1) and (0,-3)
Graph both points on the coordinate plane.
Join both points and extend the line to find the graph of the line y = 2x - 3
To find the area the represents y ≥ 2x - 3, consider any point, suppose (0,0)
Substitute (0,0) into y ≥ 2x - 3
0 ≥ 2(0) - 3
0 ≥ -3
Hence the equation satisfies.
Which means the area which has the point (0 , 0) shows the region for the equation y ≥ 2x - 3.
The graph is shown.
Answer:
The answer is the first one 30-3p
Step-by-step explanation:
GOT YOU DAWG
Step-by-step explanation:
It is (A)95° by using External Angle Property of triangles.
BTW whats up with that order C-D-B-A
Https://tex.z-dn.net/?f=23%5C%25+%5C+of+%5C+75%3D23%5C%25+%5Ctimes+75%3D%5Cfrac%7B23%7D%7B100%7D+%5C...
For this case, we must subtract the given matrices, for this we subtract term to term.
So, we have:
Equal signs are added and the same sign equals:
=
![\left[\begin{array}{ccc}-4\\-3\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C-3%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
ANswer:
![\left[\begin{array}{ccc}-4\\-3\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C-3%5C%5C0%5Cend%7Barray%7D%5Cright%5D)