Hakeem's front porch measures 9 3/4 feet by 4 feet . Estimate the area of his front porch.

Given the graph, find the distance of GH. Round to the nearest tenth.

lord [1]

Answer:

GH = 6.3 units

Step-by-step explanation:

Assuming that 1 box represents 1 unit, the coordinate pair of G = (-2, -3), while H = (0, 3).

Distance between G and H = $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$G(-2, -3) = (x_1, y_1)$

$H(0, 3) = (x_2, y_2)$

$GH = \sqrt{(0 - (-2))^2 + (3 - (-3))^2}$

$GH = \sqrt{(2)^2 + (6)^2}$

$GH = \sqrt{4 + 36} = \sqrt{40}$

$GH = 6.3 units$ (nearest tenth)

5 0

3 years ago

I need to find the surface area and volume of all three figures. If you could provide what equations you used to I will be grate

Margarita [4]

Answer:

Part 1) Sphere The surface area is equal to $SA=196\pi\ m^{2}$ and the volume is equal to $V=\frac{1,372}{3}\pi\ m^{3}$

Part 2) Cone The surface area is equal to $SA=(16+4\sqrt{65})\pi\ units^{2}$ and the volume is equal to $V=\frac{112}{3}\pi\ units^{3}$

Part 3) Triangular Prism The surface area is equal to $SA=51.57\ mm^{2}$ and the volume is equal to $V=17.388\ mm^{3}$

Step-by-step explanation:

Part 1) The figure is a sphere

a) Find the surface area

The surface area of the sphere is equal to

$SA=4\pi r^{2}$

we have

$r=14/2=7\ m$ ----> the radius is half the diameter

substitute

$SA=4\pi (7)^{2}$

$SA=196\pi\ m^{2}$

b) Find the volume

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$r=14/2=7\ m$ ----> the radius is half the diameter

substitute

$V=\frac{4}{3}\pi (7)^{3}$

$V=\frac{1,372}{3}\pi\ m^{3}$

Part 2) The figure is a cone

a) Find the surface area

The surface area of a cone is equal to

$SA=\pi r^{2} +\pi rl$

we have

$r=4\ units$

$h=7\ units$

Applying Pythagoras Theorem find the value of l (slant height)

$l^{2}=r^{2} +h^{2}$

substitute the values

$l^{2}=4^{2} +7^{2}$

$l^{2}=65$

$l=\sqrt{65}\ units$

so

$SA=\pi (4)^{2} +\pi (4)(\sqrt{65})$

$SA=16\pi +4\sqrt{65}\pi$

$SA=(16+4\sqrt{65})\pi\ units^{2}$

b) Find the volume

The volume of a cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=4\ units$

$h=7\ units$

substitute

$V=\frac{1}{3}\pi (4)^{2}(7)$

$V=\frac{112}{3}\pi\ units^{3}$

Part 3) The figure is a triangular prism

a) The surface area of the triangular prism is equal to

$SA=2B+PL$

where

B is the area of the triangular base

P is the perimeter of the triangular base

L is the length of the prism

Find the area of the base B

$B=\frac{1}{2} (2.7)(2.3)=3.105\ mm^{2}$

Find the perimeter of the base P

$P=2.7*3=8.1\ mm$

we have

$L=5.6\ mm$

substitute the values

$SA=2(3.105)+(8.1)(5.6)=51.57\ mm^{2}$

b) Find the volume

The volume of the triangular prism is equal to

$V=BL$

where

B is the area of the triangular base

L is the length of the prism

we have

$B=3.105\ mm^{2}$

$L=5.6\ mm$

substitute

$V=(3.105)(5.6)=17.388\ mm^{3}$

5 0

3 years ago

Hello guys can you help me with this?

Katyanochek1 [597]

Answer:

Step-by-step explanation:

1. Title of the graph → Comparison of the Plant Growth

2. y-axis represents the height of the plants in centimeters.

3. On day 2:

Height of plant A (plant outside) = 5.1 cm

Height of plant B (plant near the window) = 2.25 cm

4. Plant outside shows great increase in the height.

On day 5,

Height of the plant outside = 6.75 cm

Growth in height from day 2 to day 5 = 6.75 - 5.1

= 1.65 cm

Height of the plant near the window = 2.5 cm

Growth in height of the plant from day 2 to day 5 = 2.5 - 2.25

= 0.25 cm

Therefore, plant outside shows the great increase in height.

5. Plant near the window grew 0.25 cm in height.

4 0

2 years ago

Plz help i am in 6 grade ( 3 1 ) 2 +3^2 =

Fantom [35]

Answer:

Step-by-step explanation:

its 71 my dude :)

8 0

3 years ago

Read 2 more answers

the 2nd to 6th digits of the number 'b'. The number 'a': a.=.8381277236048455262835343009097967569917320013149981038679556930339

sattari [20]

Hhhhhhhhhmmmmmmmmmmmm

3 0

3 years ago