Answer:
The answer is 20,358,520
Step-by-step explanation:
Selecting 6 numbers from a collection of 52 numbers regardless of order involves a combination.
Note: if regards was taken into order of selection, this would be a permutation.
Hence, the different 6 number selections out of 52 is
52C6 = 52! / [6!*(52-6)!]
= 52!/(6!*46!)
= 20,358,520
Answer:
0.375
Step-by-step explanation: All you need to do is divide 3 and 8
Since a product in maths means the result after multiplying numbers, you need to multiply 2 prime numbers and get 4.
If we look at the prime numbers: 2, 3, 5, 7, 11, etc, we see that the only number we can multiply to get 4 is 2, or, in other words, the only multiplication of prime numbers we can do to get four is 2*2=4.
Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
D. If you were to graph this, the vertex would be at (9/8,101/4), or (1.13,25.25).
