Use distributive property:
16. 5k(3 - 4k)
15k - 20k^2
18. 6g^2(g - 8)
6g^3 - 48g^2
20. -2n^2 (5n - 9 + 4n^2)
-10n^3 + 18n^2 - 8n^4
This is a geometric sequence with first term 2 and common ratio 5.
an = a1 r^(n-1) IS THE GENERAL FORM SO HERE IT IS:-
an = 2(5)^(n-1)
+ 32
and
- 5
will do that job for you.
Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
Answer:
W=2/(P-2L)
Step-by-step explanation: