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3 years ago

What is the median of the following string or values 34, 63, 28, 7, 15, 8, 92, 37, 85, 3

Mathematics

1 answer:

mr_godi [17]3 years ago

7 0

Answer:

Median = 31

Step-by-step explanation:

Given series is :

34, 63, 28, 7, 15, 8, 92, 37, 85, 3

Arranging the above data in ascending order:

3, 7, 8, 15, 28, 34, 37, 63, 85, 92

Since n = 10 which is an even number,

∴ Median = $\frac{Sum\ of\ middle\ two\ terms}{2}$

The middle two number are 28 and 34, therefore

Median = $\frac{28 + 34}{2} = \frac{62}{2} =31$

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erik [133]

The answer for this equation is 10 gallons of water

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3 years ago

A wedding website states that the average cost of a wedding is $25,809. One concerned bride hopes that the average is less than

lapo4ka [179]

Answer:

Null hypothesis H₀ : μ = 25,809

Alternative hypothesis H₁ : μ < 25,809

2) Test Statistic = -1.44

3) Conclusion:

The result is significant, there is sufficient evidence to support the bride’s hope at the 0.10 level of significance.

Step-by-step explanation:

Given the data in the question;

Sample mean x" = 24,638

sample size n = 46

standard deviation σ = 5531

level of significance ∝ = 0.10

NULL and ALTERNATIVE HYPOTHESIS

Null hypothesis H₀ : μ = 25,809

Alternative hypothesis H₁ : μ < 25,809

TEST STATISTICS

Z = (x"-μ) / σ√n

we substitute

Z = (24,638 - 25,809) / (5531/√46)

Z = -1171 / 815.5

Z = -1.44

Test Statistic = -1.44

Now, from normal z-table;

P-value = P( Z < -1.44 ) = 0.0749

P-value = 0.0749

Since P-value ( 0.0749 ) is less than level of significance ( 0.10 ), we reject H₀.

Conclusion:

The result is significant, there is sufficient evidence to support the bride’s hope at the 0.10 level of significance.

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3 years ago

Last year a restaurant chain spent 3.3 X 106 dollars

Brums [2.3K]

I think the answer is d

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3 years ago

6x - 2 (x + 2) > 2 - 3 (x + 3)<br> whats the solution?

Gwar [14]

Answer:

x>−3/7

Step-by-step explanation:

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3 years ago

PLLLLEEEEEEAAASSSSSSSSEEEE

mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Line a passes through (2, 10) and (4, 13). So, slope of this line is

$m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}$

Line b passes through (4, 9) and (6, 12). So, slope of this line is

$m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}$

Line c passes through (2, 10) and (4,9). So, slope of this line is

$m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}$

Product of slopes of to perpendicular lines is -1.

$m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1$

$m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

$m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

Therefore, any of these lines are not perpendicular to each other.

8 0

3 years ago