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3 years ago

WILL MARK BRILLIANT!!! I need help ASAP

Mathematics

1 answer:

Rashid [163]3 years ago

5 0

Answer:

Step-by-step explanation:

Charging by the quarter mile is for purpose of making that particular taxi service seem cheaper than the others when they post a per mile charge. If this taxi company is charging .50 per 1/4 mile, they are charging $2 per mile. So we will base our equation on the per mile charge, not the per quarter-mile charge. If x is the number of mile driven (our uknown), and we have a flat fee of $2.50 regardless of how many miles we are driven, the cost function in terms of miles is

C(x) = 2x + 2.50

If we are driven 5 miles, then

C(5) = 2(5) + 2.50 so

C(5) = 10 + 2.50 and

C(5) = $12.50

It would cost $12.50 to be driven 5 miles

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3 years ago

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First option: correct. This is because angles WOX and XOZ are supplementary, so

$m\angle WOX=180^\circ-104^\circ=76^\circ$

Second option: correct. By the inscribed angles theorem, we have

$m\angle XWZ=m\angle XYZ=\dfrac{113^\circ}2=56.5^\circ$

Angles WOX and YOZ are congruent because they form a vertical pair; they both have measure 76 degrees. This means angles WXY and WZY are also congruent, since the interior angles of any triangle sum to 180 degrees in measure. Therefore triangles WXO and YZO form a side-side-side pair, and all SSS triangles are similar.

Third option: not correct. There is a theorem (not sure what the name is) regarding intersecting chords that asserts the average of the measures of arcs WY and XZ is the same as the measure of angle XOZ. This means

$\dfrac{m\widehat{WY}+113^\circ}2=104^\circ\implies m\widehat{WY}=95^\circ$

Fourth option: not correct. This is because arcs WX and XZ are not "supplementary" in the sense that they do not form a semicircle and their measures do not add to 180 degrees. We know this because it's clear that point O is not the center of the circle. If it was, then angle XOZ would be a central angle and its measure would be the same as the arc XZ it subtends.

Fifth option: correct. The theorem mentioned in the assessment of the third option makes itself useful here. We have

$\dfrac{m\widehat{WX}+m\widehat{YZ}}2=m\angle WOX\implies m\widehat{WX}+m\widehat{YZ}=2\cdot76^\circ=152^\circ$

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