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BartSMP [9]
3 years ago
14

Please help me Urgent!!!!!

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0
Your answer are options: A, B D F
YOu can just say: 8x8=64
So, evrything biger or = 64, are the answer.
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Solve the inequality: 12p + 7 > 139
8_murik_8 [283]
If you would like to solve the inequality 12 * p + 7 > 139, you can do this using the following steps:

12 * p + 7 > 139
12 * p > 139 - 7
12 * p > 132       /12
p > 132/12
p > 11

The correct result would be p > 11.
4 0
3 years ago
Read 2 more answers
How do you tell if a number is irrational or rational?
Korvikt [17]
A rational number is any number that can be expressed as a fraction
(ex: -5/2, 4 1/7, and 8/13)

An irrational number is any number that cannot be expressed as a fraction; a non-repeating, non-terminating decimal (ex: pi, 0.121231234...)

Hope this helps! :)
6 0
3 years ago
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
3 years ago
What is the derivative of the function below?
11111nata11111 [884]

g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}

8 0
2 years ago
After the 4th half life how much of the sample is left if the mass is 100g.
vazorg [7]

Answer:

\huge\boxed{\sf 6.25 \ g}

Step-by-step explanation:

After every Half life , Half of the mass is left.

After 1st Half life = 100 g / 2 = 50 g

After 2nd Half life = 50 / 2 = 25 g

After 3rd Half life = 25 / 2 = 12.5 g

After 4th Half life = 12.5 / 2 = 6.25 g

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
2 years ago
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