X2-2x-35=0x2-7x+5x-35=0x(x-7)+5(x-7)=0(x-7)(x+5)=0x-7=0 or x+5=0x=7 or x=-5 Check: x=7 ,LHS = 49-14-35 =0 =RHS x=-5, LHS = 25+10-35 =0=RHSAns: x=7 or x=-5
<span><span>x2</span>−x−12=0</span>
Ok, you can refer to the midpoint formula to find the endpoint. Here goes...
MP=(2,-7) and EP=(8,-5)
Let x represent the missing endpoint.
(8+x)/2=2 NOTE: =2 represents first number of MP and the representation of number 8 is self explanatory. You have two endpoints but need to identify the other endpoint so you divide by 2. Then, multiply by two on both sides.
2(8+x)/2 = 2*2
16+x/2=4 do the next step (simplify) on the left side of equation 16x/2=8
Now, subtract 4-8=-4 So, the x coordinated of the missing endpoint is -4.
Answer:
I believe the answer is- The mean and MAD can accurately describe the "typical" value in the symmetric data set.
Step-by-step explanation:
The other answers don't make sense because the mean and MAD are being used for symmetrical distributions and asymmetrical means uneven distributions.
Answer:
n<2
Step-by-step explanation:
3n+1 < 7
3n + 1 + (-1) < 7 +(-1)
3n < 6
(3n)/3< 6/3
n < 2
Hope this helps!!!
