The local minima of 
are (x, f(x)) = (-1.5, 0) and (7.980, 609.174)
<h3>How to determine the local minima?</h3>
The function is given as:
See attachment for the graph of the function f(x)
From the attached graph, we have the following minima:
Minimum = (-1.5, 0)
Minimum = (7.980, 609.174)
The above means that, the local minima are
(x, f(x)) = (-1.5, 0) and (7.980, 609.174)
Read more about graphs at:
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Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
Answer: 262,000? I'm just guessing
Step-by-step explanation:
one product costs $14 to produce. It is mentioned that you need to produce 14,000 products or items, so you multiply 14 by 14,000 to know the total cost of producing 14,000 items or products, the answer is 196,000, remember there is also a start-up cost of 66,000. So you must add 196,000 to 66,000 which leads to 262,000. Hope this helps :)
Answer:
Step-by-step explanation:
Given an inequality that relates the height h, in centimeters, of an adult female and the length f, in centimeters, of her femur by the equation
If an adult female measures her femur as 32.25 centimeters, we can determine the possible range of her height by plugging f = 32.25cm into the modelled equation as shown:
If the modulus function is positive then:
If the modulus function is negative then:
multiply through by -1
combining the resulting inequalities, the estimate of the possible range of heights will be
Answer:
C) Tom did not distribute to both terms in parentheses.
Step-by-step explanation:
Addition within a paranthesis has a distributive property to the multiplier outside the paranthesis. Ignoring this will lead to a wrong value for the operation.
