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3 years ago

What two numbers multiply 45 and add to 14

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

5 0

Ok to start this problem you must list two numbers that add to 14

7 and 7

9 and 5

10 and 4

6 and 8

those are the numbers that we will use for now..

Now multiply each pair of numbers and see which one equals 45

7 * 7 = 49, no

9 * 5 = 45, YES

10 * 4 = 40, No

6 * 8 = 48, No

The numbers discovered are 9 and 5

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Show the formula for finding the area of a triangle. Then find the area of a right triangle with a base of 19 cm and a height of

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The answer is 61.75 because you have to do base times height then divide that answer by two

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2 years ago

a veterinarian needs to know animals weight in kilograms. if 20 pounds is about 9 kilograms and a dog weights 30 pounds, use a r

ahrayia [7]

For this case we have the following conversion:

20 pounds = 9 kilograms

To use the table what we must do is find another relationship that allows us to find the weight in kilograms for 30 pounds.

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3 0

3 years ago

Read 2 more answers

Hi everybody!

Irina-Kira [14]

That answer is A and B pick one

5 0

2 years ago

The area of a rectangular closet is 8 square feet. The perimeter is 12 feet. What are the

3241004551 [841]

A=8ft^2
A=l•w
8=l•w
l=8/w

P=2(l+w)
12=2(8/w+w)
12=2(8/w+w/1)
12=2(8/w+w^2/w)
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8 0

2 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago