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murzikaleks [220]
3 years ago
6

What is the domain of this function? (6, 12) (10, -12) (8, 2) (20, -7)

Mathematics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

Domain: 6,10,8,20

Step-by-step explanation:

Domain is basicly the x-value.

eduard3 years ago
3 0

Answer:

The domains are 6, 10, 8, 20

Step-by-step explanation:

It's the domain because a domain is an input to a function. While the range is an output to a function.

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A sine function has the following key features:
lakkis [162]

Answer: f(x) = 6*sin( (1/8)*π*x) + 3

Step-by-step explanation:

A sine function is written as:

f(x) = A*sin(w*x + f) + M

where:

A = amplitude

w = frequency

f = phase

M = midline

Here we know that:

Frequency = 1/8π, then: w = (1/8)*π

Amplitde = 6, then A = 6

midline = 3, then M = 3

So our equation is:

f(x) = 6*sin( (1/8)*π*x + f) + 3.

Now we also know that:

y-inercept: (0,3)

This means that:

f(0) = 3 = 6*sin( (1/8)*π*0 + f) + 3 = 6*sin(f) + 3

Now we can remember that sin(0) = 0

Then we must have f = 0.

This means that the equation is:

f(x) = 6*sin( (1/8)*π*x) + 3

So the image of the function is:

4 0
3 years ago
If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x
Andrei [34K]

Answer:

\large\boxed{A.\ (x+6)^2+(y+10)^2=20}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

Finally we have

(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

5 0
4 years ago
Read 2 more answers
What is the value of the expression 2^4 + 3^2? Numerical Answers Expected!
Harrizon [31]

Answer:

25

Step-by-step explanation:

2^4+3^2\\2 \cdot 2 \cdot 2 \cdot 2+3 \cdot 3\\16+9\\25

4 0
3 years ago
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Please answer fast!!
mel-nik [20]

0.8 • 0.8 • 0.8 =0.512

3 0
4 years ago
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A theater sells tickets for a concert. Tickets for lower-level seats sell for $35 each, and tickets for upper-level seats sell f
Naya [18.7K]
A*25+b*35=10250
a      +b     = 350         | * -25

25a    + 35b= 10. 250
-25a    -25 b=  -8.750
------------------------------
            10b = 1500
            b=1500:10
             b=150  tickets cost 35 $
           
a= 350-150
            a= 200 tickets cost 25 $
8 0
3 years ago
Read 2 more answers
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