If a = first term and r = common ratio we have
a + ar + ar^2 = 13 and ar^2 / a = r^2 = 9
so r = 3
and a + 3a + 9a = 13
so a = 1
so they are 1,3 and 9
2.
in geometric series we have
4 , 4r ,4r^2 , 60
Arithmetic;
4, 4r , 4r + d , 4r + 2d
so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30
so d = 30 - 2r
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0
2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24
and the numbers are 4*3 = 12 , 4*3^2 = 36
first 3 are 4 , 12 and 36 ( in geometric)
and last 3 are 12, 36 and 60 ( in arithmetic)
The 2 numbers we ause are 12 and 36.
Answer:
x=1.5 or 0.5
Step-by-step explanation:
Not sure if I am correct
Answer:
x = 3
Step-by-step explanation:
ΔABC is 45 45 90 right triangle
The ratio of leg: hypo = a : a√2
Given: hypo AC = 6√2; so AB = BC = 6
ΔBCD is 30 60 90 right triangle
The ratio of short leg : long leg : hypo = x : x√3 : 2x
Hypo. BC = 6 = 2 (3)
So short leg BD = x = 3
Answer:
It is 9x^3.
Step-by-step explanation:
36x^4 and 45x^3.
GCF of 36 and 45 = 9
GCF of x^4 and x^3 = x^3
GCF of 36x^4 and 45x^2 = 9x^3.
Each liter of water weighs 1 kg, so the weight of the water in a cubic meter is 1,000 kg.