Answer:
P
Step-by-step explanation:
Findings are not the same
Answer:
So in order to find the missing number, we must find the difference with the numbers that we were given.
Problem #1
42-30= 12 and 84-69= 15. It's possible that each difference increases by one Let's see...
30+12= 42
42+13= 55
55+14 = 69
69+15 = 84
So for 1., all you have to do is keep adding the difference and increase it by 1 each time. If you wanted to keep increasing, you would add 84+16, then 100+17, etc.
Problem #2: As for the second one, I had trouble solving it, sorry :(.
Problem #3
3. For the third problem, 27-22= 5 and 9-1=8. It looks like each difference increased by 1.
27-22 = 5
22-6 = 16
16-7 = 9
9-8= 1
Answer is:
6162 years
Explanation:
The given equation to use is:
<span>N=Noe^-kt
First, we will need to define the variables of the equation as follows:
No : original amount of C-14 (at t=0)
N : amount of C-14 at certain time (t)
k : a constant equals </span><span>0.0001
t : the time in years
Now, we are given that:
The skeleton contains 54% of it's original amount of C-14. This means that:
N/No = 54% = 0.54
Substitute with this given in the equation given, we will find that the only unknown is the time (t). We can now solve for t as follows:
</span><span>N=Noe^-kt
This can be rewritten as:
N/No = </span>e^-kt
Now,
N/No = e^-kt
0.54 = e^(-0.0001t)
Take ln for both sides:
ln (0.54) = -0.0001t
-0.61618 = -0.0001t
t = 6161.86 years which is approximately 6162 years
Hope this helps :)
*attachment contains the missing diagram
Answer/Step-by-step explanation:
Given that RP ⟂ QS, <RPS is a right angle.
Therefore, m<RPS = 90°
Since RP bisects <SRQ, therefore m<PRS = ½ of m<SRQ.
Therefore:
m<PRS = ½*104°
m<PRS = 52°
m<S + m<RPS + m<PRS = 180° (sum of ∆)
m<S + 90° + 52° = 180° (substitution)
m<S + 142 = 180°
Subtract 142 from each side
m<S = 180° - 142°
m<S = 38°