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NeX [460]
3 years ago
12

Ten vendors are selling at an event, and an attendance of 42,000 is projected. It is anticipated that 65 percent of the attendee

s will make purchases. Assuming that each vendor has an equal chance of having an attendee prefer their products, what is the average number of customers each will serve?
Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0
For this case, the first thing we must do is calculate the number of attendees who will make purchases.
 We have then:
 (42000) * (0.65) = 27300
 We are now looking for the number of attendees that each vendor will attend.
 We have then:
 N = (27300) / (10)
 N = 2730
 Answer:
 
the average number of customers each will serve is:
 
N = 2730
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All of the points in the graph are on the same line. Find the slope of the line.
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Answer:

Step-by-step explanation:

take (1,3) and (9,7)

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3 0
3 years ago
If the output number y is -52 (y=5x-2) what is the input number? SHOW WORK
nordsb [41]

Answer:

the input number is -10

Step-by-step explanation:

output is always y

input is always x

so instead of y, put -52

-52=5x-2  add 2 to each side to ger 5x by itself

-50=5x     divide both sides by 5 to get x by itself

-10=x

x is the input so the input is -10

8 0
3 years ago
Rina draws a plan of her school on a coordinate grid. She plots the school gate at point p(-8,-1) and the library at point Q(2,5
natka813 [3]

Answer:

The coordinates of the science lab is:

x = -14/3  ,  y = 1

Step-by-step explanation:

∵ P is (-8 , -1) and Q is (2 , 5)

∵ The point of the science lab is (x , y)

∵ The science lab point divided PQ at ratio 2 : 1 from Q (two thirds PQ)

∴ x=\frac{m_{1}x_{p}+m_{2}x_{q}}{m_{1}+m_{2}}

∴ y=\frac{m_{1}y_{p}+m_{2}y_{q}}{m_{1}+m_{2}}

∴ x=\frac{2(-8)+1(2)}{1+2}=\frac{-14}{3}

∴ y=\frac{2(-1)+1(5)}{2+1}=\frac{3}{3}=1

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5 0
3 years ago
Simplify 3(r + 4) - 5r
Nimfa-mama [501]

Answer: 12-2r

Step-by-step explanation:

3r+12-5r

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6 0
2 years ago
Read 2 more answers
A chemical factory has 2 cylindrical chemical tanks, one containing Chemical X and the other containing Chemical Y. The tank con
Mashutka [201]
The tank with Chemical X "takes up" a space of 25ft³.  Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume.  The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:
\frac{25}{1.5}=\frac{1.5V}{1.5} \\16 \frac{2}{3}=V
To find the volume of a cylinder, we find the base area and multiply by the height.  We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:
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We would now divide both sides by 3 2/10:
\frac{16 \frac{2}{3}}{3 \frac{2}{10}}= \frac{3 \frac{2}{10}h}{3 \frac{2}{10}}
This is the same as:
\frac{\frac{50}{3}}{\frac{32}{10}}=h \\ \\ \frac{50}{3}* \frac{10}{32}=h \\ \\ \frac{500}{96}
So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.
8 0
3 years ago
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