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3 years ago

Can someone help me on these 2 questions?

Mathematics

1 answer:

bonufazy [111]3 years ago

7 0

7. x=20

8. x=19

Step-by-step explanation:

7. The shape is a parallelogram and the angles that are labeled are opposite from each other, meaning that they are congruent. So, 4x-40=2x (and solve)

8. Same case as last time (parallelogram), and the angles labeled are congruent. So, 2x+19=3x (and solve)

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EHLP HASTT PLEASE 5 MINUTESS

kykrilka [37]

Answer:

its a

Step-by-step explanation:

x is how many rides and a ride is five tickets. multiply them to get how man rides hes been on

6 0

3 years ago

Solve the equation algebraically -8(3y+5)=14

inysia [295]

Answer:

y = -2.25

Step-by-step explanation:

-8(3y+5) = 14

-8(3y+5)/-8 = 14/-8

3y+5 = -1.75

3y+5-5 = -1.75-5

3y = -6.75

3y/3 = -6.75/3

y = -2.25

6 0

3 years ago

Sorry to be annoying again I just really suck at math and I haven't slept yet

Vesna [10]

Answer:

50.33 mi.

Step-by-step explanation:

GIVEN :-

Coordinates of :-

Home = (0 , 0)
School = (4 , 3)
Pizza place = (-8 , 2)
Movie Theater = (-4 , -6)
Park = (7 , -5)

TO FIND :-

Total distance travelled on Friday & Saturday.

GENERAL FORMULAE TO BE USED IN THIS QUESTION :-

Lets say there are two points A & B on a cartesian plane whose coordinates are (x₁ , y₁) & (x₂ , y₂).

Distance between A & B = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

SOLUTION :-

According to question ,

On Friday , you -

leave school and go to pizza palace. Distance travelled from school to pizza palace = $\sqrt{(4 -(-8) )^2 + (3 - 2)^2} = \sqrt{(12)^2 + (1)^2} = \sqrt{145}$ ≈ 12.04 mi.
go to movie theater after pizza palace. Distance travelled from pizza palace to movie theater = $\sqrt{[(-4) -(-8)]^2 + (-6 - 2)^2} = \sqrt{(4)^2 + (-8)^2} = \sqrt{80}= 4\sqrt{5}$ ≈ 8.94 mi.
come back to your home after the movies. Distance travelled from theater to home = $\sqrt{[0-(-4)]^2 + (0 - 6)^2} = \sqrt{(4)^2 + (-6)^2} = \sqrt{52} = 2\sqrt{13}$ ≈ 7.21 mi.

⇒ On Friday , total distance travelled = 12.04 + 8.94 + 7.21 = 28.19 mi.

On Saturday , you -

go to park from your home. Distance travelled from home to park = $\sqrt{(7 -0 )^2 + (-5 - 0)^2} = \sqrt{(7)^2 + (-5)^2} = \sqrt{74}$ ≈ 8.6 mi.
go to school after going to park. Distance travelled from park to school = $\sqrt{(4 -7 )^2 + [3 - (-5)]^2} = \sqrt{(-3)^2 + (8)^2} = \sqrt{73}$ ≈ 8.54 mi.
go to home after playing basketball in school. Distance travelled from school to home = $\sqrt{(0 -4 )^2 + (0 - 3)^2} = \sqrt{(-4)^2 + (-3)^2} = \sqrt{25}$ = 5 mi.

⇒ On Saturday , total distance travelled = 8.6 + 8.54 + 5 = 22.14 mi.

∴ Total distance travelled on Friday & Saturday = 28.19 + 22.14 = 50.33 mi.

3 0

3 years ago

Car is moving on a circle on a plane. At time t (seconds), its x-coordinate is given by x(t) = 10 sin(200t + 3) + 30 while its y

Aleks [24]

Answer:

we have centre of circle as (30,40) and radius = 1

Step-by-step explanation:

Given that a car is moving on a circle on a plane.

At time t (seconds),

$x(t) = 10 sin(200t + 3) + 30$

and

$y(t) = 10 cos(200t + 3) + 40$

$x-30 = 10 sin(200t + 3) \\y-40 = 10 cos(200t + 3) + 40$

when we square and add both the equations we get

$(x-30)^2 + (y-40)^2 = 1$

(since sin square + cos square = 1 always)

i.e. we have centre of circle as (30,40) and radius = 1

3 0

3 years ago

#11 how do you do this someone please help me

stiv31 [10]

11.) You pay 620 to rent a hotel room for 4 weeks. Total cost include an initial deposit plus a weekly fee of 125.
a)y=(rate per week)x+deposit
620=125x+deposit
620=125(4)+deposit
620=500+deposit
620-500=deposit
120=deposit
y=125x+120
b) y-intercept is the deposit, at 120

4 0

3 years ago