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2 answers:
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Answer:
Graph A → Equation A → Table B → Property D
Graph D → Equation B → Table A → Property B
Graph B → Equation C → Table C → Property E
Graph C → Equation D → Table E → Property A
Graph E → Equation E → Table D → Property C
Step-by-step explanation:
Graph A corresponds to equation A, x·y = 2, and Table B → Property D
xy = 2 has a vertical asymptote at x = 0, and a horizontal asymptote at y = 0
y = 2/x, when x = 0, y = ∞
Graph D corresponds to equation B, + 1 which corresponds to table A → Property B
The domain extends from (-∞, ∞), and [1, -∞)
Graph B corresponds to equation C, -(x + 2)² which gives the values in Table C and Property E wich is a horizontal shift of 2 units left and a reflection across the x-axis
Graph C corresponds to equation D, (1/3)·x - 2, which gives the values on Table E and Property A
The y-intercept of (1/3)·x - 2 = (0, -2), and the x-intercept = (6, 0)
Graph E corresponds to equation E, x³ = y, which gives the values on Table D Property C, y is x cubed
Answer: The time at which the distance between the two is 150 miles is 1.3 hr.
Step-by-step explanation:
Step 1: Sketch the problem as shown in the attached image.
The problem can be solved using Pythagoras theorem since the sketch is a right angled triangle.
It follows the equation x² + y² = 15².
The distance covered by Greg is given by <em>x mi</em>, and that of Erin is given by <em>y mi</em>.
Step 2: To derive the distance covered by Erin and Greg, we use the formula <em>Speed = distance ÷ time.</em>
Which by cross-multiplying gives <em>distance = speed × time</em>.
Let time taken to cover the distance be <em>t h</em>.
Given that Speed of Erin is 9 mph and that of Greg is 7 mph.
Hence, distance covered by Greg, x = 7 × t = 7t.
Distance covered by Erin, y = 9 × t = 9t.
Step 3: Insert the terms x and y into the Pythagoras equation x² + y² = 15² and solve for <em>time t.</em>
(7t)² + (9t)² = 15²
49t² + 81t² = 225
(49 + 81)t² = 225
t² = 225/(49 + 81)
t² = 225/130
t² = 1.730769231
t = √1.730769231
t = 1.315587029
t = 1.3hr
Hence the time at which the distance between the two is 150 miles is 1.3 hr.
