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polet [3.4K]
3 years ago
13

Help!! I have no clue

Mathematics
2 answers:
netineya [11]3 years ago
5 0

So we know that an ordered pair looks like (x,y), right? For this inequality, we're supposed to plug in the values of x and y. If it isn't true, then the inequality does not represent the ordered pair.

First option: (0,1)

2x + 3y \geq -1 --> 2(0) + 3(1) \geq -1 --> 5 \geq -1

So this option is correct.

Second option: (-2,1)

2x + 3y \geq -1 --> 2(-2) + 3(1) \geq -1

--> -4 + 3 \geq -1 --> -1 \geq -1

This is also correct.

Third option: (-6,0)

2(-6) + 3(0) \geq -1 --> -12 \geq -1

This is not true, so this option is not correct.

Fourth option: (0,-1)

2(0) + 3(-1) \geq -1 --> -3 \geq -1

This is not correct.

Fifth option: (2,-1)

2(2) + 3(-1) \geq -1 --> 4 - 3 \geq -1

This is correct.

VikaD [51]3 years ago
3 0

okay so you just plug in the x and ys. x is the first number, y is the second. then you just do them all out

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Leah drives her truck 270KM in the same time Deborah drives her car 250KM. If Leah drives 4km/h faster than Deborah. What is eac
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Answer:

Leah: 54km/h

Deborah: 50 km/h

Step-by-step explanation:

250+4x=270

4x=20

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both drove 5 hours

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3 years ago
At a candy store, Erika bought 3 kilograms of cinnamon red hors and 1 kilogram of gummy bears for $21.00. Meanwhile, trene bough
prisoha [69]

The cost of one kilogram of cinnamon red hots is $4.00 and cost of one kilogram of gummy bears is $9.00

Step-by-step explanation:

Let,

Cost of one kilogram of cinnamon red hots = x

Cost of one kilogram of gummy bears = y

According to given statement;

3x+y=21    Eqn 1

3x+3y=39   Eqn 2

Subtracting Eqn 1 from Eqn 2

(3x+3y)-(3x+y)=39-21\\3x+3y-3x-y=18\\2y=18

Dividing both sides by 2

\frac{2y}{2}=\frac{18}{2}\\y=9

Putting y=9 in Eqn 1

3x+9=21\\3x=21-9\\3x=12

Dividing both sides by 3

\frac{3x}{3}=\frac{12}{3}\\x=4

The cost of one kilogram of cinnamon red hots is $4.00 and cost of one kilogram of gummy bears is $9.00

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/1332667
  • brainly.com/question/1349456

#LearnwithBrainly

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3 years ago
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