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Sav [38]
3 years ago
10

Is 21,063 divisible by three? If it is, write a number as a product of three and another factor if not, explain

Mathematics
1 answer:
Zarrin [17]3 years ago
4 0
Twenty-one thousand and sixty-three divided by three is 7021

First, take any number (for this example it will be 492) and add together each digit in the number (4+9+2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).If a number is a multiplication of 3 consecutive numbers then that number is always divisible by 3. This is useful for when the number takes the form of (n * (n - 1)*(n + 1))Example: 492 (The original number). 4 + 9 + 2 = 15 (Add each individual digit together). 15 is divisible by 3 at which point we can stop. Alternatively we can continue using the same method if the number is still too large: 1 + 5 = 6 (Add each individual digit together). 6 ÷ 3 = 2 (Check to see if the number received is divisible by 3). 492 ÷ 3 = 164 (If the number obtained by using the rule is divisible by 3, then the whole number is divisible by 3)
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hodyreva [135]

<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>

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  • A polygon with 10 sides ( Decagon )

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<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

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<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

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\qquad \diamond \:  \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \:  \star

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Putting the given values, we get,

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\sf \dashrightarrow Exterior ~angle =  \dfrac{360  ^\circ}{10} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \frac{36 \cancel{0}^\circ}{ \cancel{10}} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\  \\

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\underline{ \rule{227pt}{2pt}} \\  \\

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