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Sav [38]
3 years ago
10

Is 21,063 divisible by three? If it is, write a number as a product of three and another factor if not, explain

Mathematics
1 answer:
Zarrin [17]3 years ago
4 0
Twenty-one thousand and sixty-three divided by three is 7021

First, take any number (for this example it will be 492) and add together each digit in the number (4+9+2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).If a number is a multiplication of 3 consecutive numbers then that number is always divisible by 3. This is useful for when the number takes the form of (n * (n - 1)*(n + 1))Example: 492 (The original number). 4 + 9 + 2 = 15 (Add each individual digit together). 15 is divisible by 3 at which point we can stop. Alternatively we can continue using the same method if the number is still too large: 1 + 5 = 6 (Add each individual digit together). 6 ÷ 3 = 2 (Check to see if the number received is divisible by 3). 492 ÷ 3 = 164 (If the number obtained by using the rule is divisible by 3, then the whole number is divisible by 3)
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Which value represents a horizontal shift (left and right) in the following function y=a*sin(bx-c)+d
grigory [225]
The value is C because it represents the shift

5 0
3 years ago
Jason states that Triangle A B C is congruent to triangle R S T. Kelley states that Triangle A B C is congruent to triangle T S
Brilliant_brown [7]

Answer:

The correct option is;

Jason's statement is correct. RST is the same orientation, shape, and size as ABC

Step-by-step explanation:

Here we have

ABC = (2, 1), (3, 3), (4, 1)

RST = (-4, -2), (-3, 0), (-2, -2)

Therefore the length of the sides are as follows

AB = \sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}

AC = \sqrt{(2-4)^2+(1-1)^2} =2

BC = \sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}

For triangle SRT we have

RS = \sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}

RT = \sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2

ST = \sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}

Therefore their dimensions are equal

However the side with length 2  occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST

That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.

4 0
3 years ago
Read 2 more answers
Find −315÷134. Write your answer as a mixed number in simplest form.
kipiarov [429]

Answer:

-2\frac{47}{134}

Step-by-step explanation:

-2\frac{47}{134} = -\frac{315}{134}

134can go into -315twice at the most, so doubling 134will give us 268, which leaves us with 47left over to reach 315, which is why 47is the numerator. The remainder is ALWAYS the numerator.

I am joyous to assist you anytime.

3 0
3 years ago
Help me!!!!!!!!!!! Help help help
kakasveta [241]

Answer:

5 × \frac{1}{100}

Step-by-step explanation:

4*100+2*10+3*1+6*\frac{1}{10}+x+9*\frac{1}{1000}=423.659\\4*100+2*10+3*1+6*0.1+x+9*0.001=423.659\\400+20+3+0.6+x+0.009=423.659\\423.609+x=423.659\\x=0.05\\\\50*\frac{1}{10}=5\\\\5*\frac{1}{100}=0.05\\\\50=50\\\\5*0.05=0.25

8 0
2 years ago
Find the missing lengths of the sides
Ket [755]

ANSWER

The correct answer is C

EXPLANATION

The given triangle is a right triangle. Since two angles are equal, it is a right isosceles triangle.

This implies that, x=8 units.

Using Pythagoras Theorem,

{y}^{2}  =  {8}^{2}  +  {8}^{2}

This implies that:

{y}^{2}  = 64  +  64

{y}^{2}  =128

Take positive square root,

{y}  =  \sqrt{128}

{y}  = 8 \sqrt{2}

The correct answer is C

5 0
3 years ago
Read 2 more answers
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