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Sav [38]
3 years ago
10

Is 21,063 divisible by three? If it is, write a number as a product of three and another factor if not, explain

Mathematics
1 answer:
Zarrin [17]3 years ago
4 0
Twenty-one thousand and sixty-three divided by three is 7021

First, take any number (for this example it will be 492) and add together each digit in the number (4+9+2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).If a number is a multiplication of 3 consecutive numbers then that number is always divisible by 3. This is useful for when the number takes the form of (n * (n - 1)*(n + 1))Example: 492 (The original number). 4 + 9 + 2 = 15 (Add each individual digit together). 15 is divisible by 3 at which point we can stop. Alternatively we can continue using the same method if the number is still too large: 1 + 5 = 6 (Add each individual digit together). 6 ÷ 3 = 2 (Check to see if the number received is divisible by 3). 492 ÷ 3 = 164 (If the number obtained by using the rule is divisible by 3, then the whole number is divisible by 3)
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miv72 [106K]

acceleration of ball is \frac{-1}{3}\,\,m/sec^2

Step-by-step explanation:

Initial Velocity = 12m/sec

time = 36 s

Final Velocity 0 m/sec (ball comes to stop)

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The formula used to find acceleration is:

Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}

Putting values and finding acceleration:

Acceleration=\frac{Final\,\,Velocity-Initial\,\,Velocity}{Time}

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So, acceleration of ball is \frac{-1}{3}\,\,m/sec^2

Keywords: Acceleration

Learn more about Acceleration at:

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8 0
3 years ago
Solving quadratic equations is one of the main topics of this unit. Some quadratic equations can be solved with only one method,
Mariana [72]

Hi there!

Many things we do in everyday life have a variety of ways we can go about accomplishing them, but we most often choose the most practical and efficient method.

Efficiency saves time and prevents over-complication, which may lead to errors.

We might need to identify the specifics of the task and its circumstances to be able to determine the most efficient method to do it.

Solving a quadratic equation, we also must think about the most efficient method that can lead us to the correct answer. And doing so, we must identify the circumstances of the equation; Can it be solved by factoring? Is it easy to factor? What form is this quadratic equation in?

For example, let's say we're given the equation (x-1)(x+2)=0. This is an equation in factored form. In these kinds of scenarios, we can <em>easily</em> solve by setting each term equal to 0 (the Zero Product Property). This is the <em>most efficient </em>method:

x-1=0 --> x=1

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I hope this helps!

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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