The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:
700/383
Step-by-step explanation:
<span>"The company pays $55 a day for food and lodging and $0.45 for each mile traveled" means that if she travels
m miles and is on a trip for
x days then Rita will receive:
55x + 0.45m dollars.
Rita drove 300 miles, means that m=300. Thus </span>
55x + 0.45m becomes <span>
</span>

(dollars.)
She was reimbursed $2,335 means that

.
Part A:

.
Part B:
We are given the equation 55x+135=2,335. Subtracting 135 from both sides we have:
55x=2,335-135=2,200.
Dividing both sides by 55, we get: x=2,200/55=40.
Part C: since x represents the number of days Rita spend on this trip, and x=40, then Rita spent 40 days on this trip.
Hey!~
The order of the fractions from least to greatest would be:
1/5, 2/8, 4/10.
Hope this helps and have a great day!
-Lindsey
Hold on let me go do my research I’ll brb .