Answer:
The least score the student can get is 71 to get an overall B average at the end of the year.
Step-by-step explanation:
Let the score she needs to get be = x
We now have to take the mean of all the five subjects <em>(including x)</em> and equate it to the least score she can have to get a B grade.
Let us take the least score the student needs to get a B grade to be 85
Mean of all 5 scores =
The least score the student can get is 71 to get an overall B average at the end of the year.
Answer:
it is B
Step-by-step explanation:
<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!