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AleksandrR [38]
2 years ago
9

Write an inequality to model the situation.

Mathematics
2 answers:
svet-max [94.6K]2 years ago
8 0

Answer:

n >21

Step-by-step explanation:

The number exceeds 21 or is greater than 21.

‘>’ represents greater than.

Let the number be n.

n >21

Makovka662 [10]2 years ago
3 0
N > 21 is the answer
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Simplify 4x^6/2x^4 step by step <br><br> please<br><br> thanks
mrs_skeptik [129]
Ok so you have 4, x^6 / 2, x^4. Now divide the coefficient so 4/2=2. So 2 x^6/x^4, now subtract the numerator by the denominator so x^6-x^4=x^2 so now you have 2x^2

Answer: 2x^2
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3 years ago
Factor the expression.<br> 9y^2– 36
Nata [24]

Answer:

Answer: 9 (y - 2) (y + 2)

Step-by-step explanation:

Factor the following:

9 y^2 - 36

Factor 9 out of 9 y^2 - 36:

9 (y^2 - 4)

y^2 - 4 = y^2 - 2^2:

9 (y^2 - 2^2)

Factor the difference of two squares. y^2 - 2^2 = (y - 2) (y + 2):

Answer: 9 (y - 2) (y + 2)

5 0
3 years ago
Vasko was renting a high performance bicycle for his Olympic training. Bicycle A is $25 per month and requires a down payment of
Agata [3.3K]
You need an equation system.

First, translate the text into equations :

y = total price for the bike
x = number of months

first bike :
y = 25x + 500

second bike :
y = 50x + 200

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7 0
3 years ago
PLEASE HELP ME!!
Dmitry_Shevchenko [17]
It’s 18. 1/2 b*h b=4 h=9
8 0
3 years ago
Answer this question
Murljashka [212]

Answer:

a = p * q

b = p * s + q * r

c = r * s

Step-by-step explanation:

In the trinomial ax² + bx + c

a is the coefficient of x²

b is the coefficient of x

c is the numerical term

∵ The trinomial is ax² + bx + c

∵ Its factors are (px + r) and (qx + s)

∴ ax² + bx + c = (px + r)(qx + s)

∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)

∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs

∴ ax² + bx + c = pqx² + (ps + qr)x + rs

→ By comparing the two sides

∵ ax² = pqx² ⇒ divide both sides by x²

∴ a = pq

∵ bx = (ps + qr)x ⇒ Divide both sides by x

∴ b = ps + qr

∴ c = rs

∴ a = p * q

∴ b = p * s + q * r

∴ c = r * s

5 0
3 years ago
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