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LiRa [457]
2 years ago
10

One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At mi

dnight the temperature was −16.8 degrees. What was the temperature at 9 p.m.? Enter your answer into the box.
Mathematics
2 answers:
Thepotemich [5.8K]2 years ago
8 0

Answer:

u r smart

Step-by-step explanation:

aliina [53]2 years ago
5 0

Answer:

- 4.2 degrees

Step-by-step explanation:

If the drop was from temp 0 at 8 pm to temp -16.8 at midnight (4 hours later)

then,the drop is given by the rate: -16.8/4 = - 4.2 degrees per hour

Therefore, at 9 pm the temperature was:

0 degrees - 4.2 degrees = - 4.2 degrees

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SashulF [63]

The 68-95-99.7 rule tells us 68% of the probability is between -1 standard deviation and +1 standard deviation from the mean. So we expect 75% corresponds to slightly more than 1 standard deviation.

Usually the unit normal tables don't report the area between -σ and σ but instead a cumulative probability, the area between -∞ and σ. 75% corresponds to 37.5% in each half so a cumulative probability of 50%+37.5%=87.5%. We look that up in the normal table and get σ=1.15.

So we expect 75% of normally distributed data to fall within μ-1.15σ and μ+1.15σ

That's 288.6 - 1.15(21.2) to 288.6 + 1.15(21.2)

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3 years ago
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VikaD [51]
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3 years ago
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kiruha [24]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
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Answer:

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3 years ago
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Step-by-step explanation:

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