For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.
For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).
Thus, there are 16 possible sums when three six-sided dice are rolled.
Therefore, from the pigeonhole principle, <span>the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.
The pigeonhole principle states that </span><span>if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.
That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.
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Answer:
A= 66.6667
B = 333.3333
Step-by-step explanation:
Initial value of A = $20
Initial value of B = $80
Initial total=$ 28000
A moves up 50%= 20+(0.5*20)
A moves up 50% = 20+10
A moves up 50% =$ 30
B double it values = $80*2
B double it values = $160
Now total value is = $54000
A20+B80= 28000... equation 1
A30+B160= 54000.... equation 2
Multiplying equation 1 * 2
Multiplying equation 2 * 1
A40 +B160 = 56000
A30+B160= 54000
A30 = 2000
A= 2000/30
A= 200/3
A= 66.6667
A20+B80= 28000
Substituting A
200/3 (20) +B80= 28000
B80= 28000-4000/3
B80= 80000/3
B= 80000/240
B = 333.3333
Answer:
the answer your looking for is a pyramid
Step-by-step explanation:
Answer:
16.
How to find... ↓
The small triangle is 1/3 size of the big triangle.
If this is the case, find the LCF here, 4, and multiply each angle's value by the least common factor, 4.
3 x 4 (bottom) = 12
5 x 4 (right side) = 20
4 x 4 (left side <em>the missing side) </em>= 16
Therefore,
The missing side value, <em>x</em>, is 16.
Answer:
no because it doesnt pass the vertical line test
Step-by-step explanation:
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