9514 1404 393
Answer:
y = (5/27)(x -7)^2 -5/3
Step-by-step explanation:
Use the given points to find the unknowns in the equation.
If the axis of symmetry is x=7, then the equation can be written in the form ...
y = a(x -7)^2 +b
Filling in the two point values, we have two equations:
0 = a(4 -7)^2 +b ⇒ 9a +b = 0
5 = a(1 -7)^2 +b ⇒ 36a +b = 5
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Subtracting the first equation from the second, we have ...
(36a +b) -(9a +b) = (5) -(0)
27a = 5
a = 5/27
Substituting that value into the first equation gives ...
9(5/27) +b = 0
5/3 +b = 0
b = -5/3
So, the quadratic can be written in vertex form as ...
y = (5/27)(x -7)^2 -5/3
Answer:
Step-by-step explanation:
<u>Complete question:</u>
Refer the attached diagram
<u>Answer:</u>
In reference to the attached figure, (-∞, 2) is the value where (f-g) (x) negative.
<u>Step-by-step explanation:</u>
From the attached figure, it shows that given data:
f (x) = x – 3
g (x) = - 0.5 x
To Find: At what interval the value of (f-g) (x) negative
So, first we need to calculate the (f-g) (x)
(f – g ) (x) = f (x) – g (x) = x-3 - (- 0.5 x)
⇒ (f - g) (x) =1.5 x - 3
Now we are supposed to find the interval for which (f-g) (x) is negative.
⇒ (f - g) (x) = x - 3+ 0.5 x = 1.5 x – 3 < 0
⇒ 1.5 x – 3 < 0
⇒ 1.5 x < 3
⇒ 
⇒ x < 2
Thus for (f - g) (x) negative x must be less than 2. Thereby, the interval is (-∞, 2). Function is negative when graph line lies below the x - axis.
Find the difference then put it over (divide it from) the original.
Answer:
60
Step-by-step explanation:
so you have a rectangle that has the lengths of 5 and x+2 and x is equal to 10, you add 10 and 2 and get 12 then you do 5 times 12 and get 60.
5(x+2) x=10
10+2=12
5x12=60
