2 years ago

Two consecutive positive integers have a product of 132. what are the integers?

1 answer:

3 0

$x(x+1)=132\implies x^2+x-132=(x-11)(x+12)=0$

If $x>0$ , that leaves you with $x=11$ , and so the two integers are 11 and 12.

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bagirrra123 [75]

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