Basically a covalent bond would have been made based on two atoms so that it can collaboratively set a trace of more electrons. Although there is no atom that is zero which if it had that then it would considerably be a net charge which it is not from this problem. What makes it unique about it is that this attractive force from creating the bond of the electrons that would be purposely activated that are the nuci for constructive used into two atoms.
Answer:
295.96 K ( = 22.81 degrees C)
Explanation:
PV = n RT R = .082057 L-Atm / (K-Mol) n = 3.5 P = 1 atm V = 85 liters
(1)(85) = 3.5 (.082057)(T)
solve for T = 295.96 K
The molar mass of a substance is 47.88 g/mol because in Titanium there is 47.88 g/mol <span> there is one mole, or 6.022 x 10</span>23<span>titanium atoms.</span>
Answer:
5. An element's mass number tells the number of protons in its nucleus.
Atomic
6. Negatively charged particles in an atom are called electrons.
True
7. The cloud model of the atom describes the location of electrons as specific orbits around the nucleus.
Bohr
8. Atoms with the same number of protons but different numbers of neutrons are called isomers.
Isotopes
9. The sum of the protons and neutrons in an atom is called the atomic number.
Mass
10. An object that helps explain ideas about the natural world is called a model.
True
11. Mendeleev arranged his periodic table in order of increasing atomic number.
Mass
12. The rows in the periodic table are called periods.
True
13. Moving across the periodic table from left to right, one finds, in order, metals, then gases, then nonmetals.
Metalloids
14. Another name for a period is a family.
Group
15. On the periodic table, elements in the same column have similar properties.
True
Explanation:
Answer: The empirical formula of X is 
.
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 62.4 g
Mass of H = 4.19 g
Mass of O = 33.2 g
Step 1 : convert given masses into moles.
Moles of C=
Moles of H=
Moles of O = 
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For O =
The ratio of C: H: O = 2.5 : 2 : 1
Converting it into simple whole number ratios by multiplying by 2:
Hence the empirical formula of X is .
