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2 years ago

Which of these is an example of water in liquid form

Chemistry

2 answers:

mylen [45]2 years ago

8 0

Answer:

river or lake

Explanation:

skad [1K]2 years ago

4 0

Answer:

???????????????????????

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Describe what happens to the mass number and the atomic number of a nuclide during alpha decay.

Digiron [165]

Answer:

The answer to your question is: The mass number will be 4 units lower.

Explanation:

Alpha particles are Helium atoms, which have a mass number of 4 and atomic number of 2.

When an alpha particle is released, the original atom loses 2 protons and and 2 neutrons an we can see in the example.

²²⁶ ₈₈ Ra ⇒ ²²² ₈₆ Rn + ⁴₂ He

3 0

3 years ago

Read 2 more answers

A 5.000 g mixture contains strontium nitrate and potassium bromide. Excess lead(II) nitrate solution is added to precipitate out

scZoUnD [109]

Answer: The mass percent of potassium bromide in the mixture is 9.996%

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For lead (II) bromide:

Given mass of lead (II) bromide = 0.7822 g

Molar mass of lead (II) bromide = 367 g/mol

Putting values in equation 1, we get:

$\text{Moles of lead (II) bromide}=\frac{0.7822g}{367g/mol}=0.0021mol$

The chemical equation for the reaction of lead (II) nitrate and potassium bromide follows:

$2KBr+Pb(NO_3)_2\rightarrow PbBr_2+2KNO_3$

By Stoichiometry of the reaction:

1 mole of lead (II) bromide is produced from 2 moles of potassium bromide

So, 0.0021 moles of lead (II) bromide will be produced from = $\frac{2}{1}\times 0.0021=0.0042mol$ of potassium bromide

Now, calculating the mass of potassium bromide by using equation 1, we get:

Molar mass of KBr = 119 g/mol

Moles of KBr = 0.0042 moles

Putting values in equation 1, we get:

$0.0042mol=\frac{\text{Mass of KBr}}{119g/mol}\\\\\text{Mass of KBr}=0.4998g$

To calculate the percentage composition of KBr in the mixture, we use the equation:

$\%\text{ composition of KBr}=\frac{\text{Mass of KBr}}{\text{Mass of mixture}}\times 100$

Mass of mixture = 5.000 g

Mass of KBr = 0.4998 g

Putting values in above equation, we get:

$\%\text{ composition of KBr}=\frac{0.4998g}{5.000g}\times 100=9.996\%$

Hence, the percent by mass of KBr in the mixture is 9.996 %

5 0

2 years ago

How many grams of NH3 can be produced from 12.0g of H2?

RSB [31]

Answer:

Balanced reaction:

3 H2 (g) + N2 (g) → 2 NH3 (g)

Use stoichiometry to convert g of H2 to g of NH3. The process would be:

g H2 → mol H2 → mol NH3 → g NH3

12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3

Explanation: See above

Hope this helps, friend.

8 0

1 year ago

Martha ran 420 m, and Cole ran 60 m less than Martha. The distance Kate ran is right in the middle of Martha and Cole's distance

prohojiy [21]

Answer:

390 m

Explanation:

Martha ran 420 m

Cole ran 60 m less than Martha = 420 m - 60 m = 360 m

The distance Kate ran is right in the middle of Martha and Cole's distances

Kate distance = (420 + 360) / 2 = 780 / 2 = 390 m

8 0

2 years ago

3.14 What is this in scientific notation

Molodets [167]

= 3.14 × 10 with the power of 0
(scientific notation)

= 3.14e0
(scientific e notation)

= 3.14 × 100
(engineering notation)
(one)

= 3.14
(real number)

3 0

2 years ago