All categories

4 years ago

Express each percent as a decimal: 7 1/2%

2 answers:

7 0

the answer is 0.075.

to convert a percent to decimal you must move the decimal point two places to the left. so for 7.5% you would move the decimal spot two places to the left leaving you with 0.075. think about it this way: a percent is out of 100 and 0.07 read out loud is “seven hundredths” (7 out of 100).

Gre4nikov [31]4 years ago

5 0

Answer:

0.075

Step-by-step explanation:

To represent 7 1/2 as a decimal, it would be 0.075 since there are 7 hundredths and half a hundredth.

You might be interested in

I really dont get this please help just A, B, and C

alexandr402 [8]

The pic is kinda blurry so I can’t read it

4 0

4 years ago

The following annual expenses for car insurance, vacation, and home repairs for the Clark family are $1130, $700, and $468, resp

eimsori [14]

Answer:

A) $192

Step-by-step explanation:

Given:

Yearly expense of Car insurance = $1130

Yearly expense of Vacation = $700

Yearly expense of home repairs = $468

we need to find the monthly allowance of Clark family.

First we find the total annual expense of Clark family.

Total Annual expense is equal to sum of Yearly expense of Car insurance and Yearly expense of Vacation and Yearly expense of home repairs.

Framing in equation form we get;

Total annual expense = $\$1130 + \$700+\$468 = \$2298$

Now we know that;

Number of months in a year = 12 months.

Total Monthly allowance will be equal to Total annual expense divided by Number of months in year.

Framing the equation we get;

Total Monthly allowance = $\frac{\$2298}{12}= \$191.5$

Rounding to nearest dollar we get;

Total Monthly allowance of Clark family is $192.

6 0

4 years ago

Read 2 more answers

How to solve the following quadratic equations; 2L, m, o, 3a and g

s2008m [1.1K]

Answer:

Please see the attached pictures for full solution.

8 0

4 years ago

Choose all of the equations that graph as an increasing function.

Allushta [10]

Answer:

A. y = -(-x) +7 = x + 7

D. y = 0.05x + 10

3 0

3 years ago

A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg

polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

$P(X = x) = nCx p^{x} q^{n - x}$

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662$

Finally, the probability that 2 or fewer students will withdraw is

$P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355$

b) Compute the probability that exactly 4 will withdraw.

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304$

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716$

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0

4 years ago